8. What is the resistance ([tex]\(R\)[/tex]) in a circuit with a voltage ([tex]\(V\)[/tex]) of 220 volts and a current ([tex]\(I\)[/tex]) of 5.2 amps?

Round your answer to the nearest tenth of an ohm.



Answer :

Sure! Let’s go through the process step-by-step to find the resistance in the circuit.

Given:
- Voltage [tex]\( V = 220 \)[/tex] volts
- Current [tex]\( I = 5.2 \)[/tex] amps

We need to find the resistance [tex]\( R \)[/tex] and round it to the nearest tenth.

1. Ohm's Law:

Ohm's Law states that [tex]\( V = IR \)[/tex]. Here, [tex]\( V \)[/tex] is the voltage, [tex]\( I \)[/tex] is the current, and [tex]\( R \)[/tex] is the resistance.

2. Formula to find Resistance:

Rearranging the formula [tex]\( V = IR \)[/tex] to solve for [tex]\( R \)[/tex]:
[tex]\[ R = \frac{V}{I} \][/tex]

3. Substitute the given values:
[tex]\[ R = \frac{220 \text{ volts}}{5.2 \text{ amps}} \][/tex]

4. Calculate the resistance:

Performing the division:
[tex]\[ R \approx 42.30769230769231 \text{ ohms} \][/tex]

5. Round to the nearest tenth:

The resistance to the nearest tenth of an ohm is:
[tex]\[ R \approx 42.3 \text{ ohms} \][/tex]

Therefore, the resistance in the circuit with a voltage of 220 volts and a current of 5.2 amps is approximately [tex]\( 42.3 \)[/tex] ohms when rounded to the nearest tenth.