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Arrange the equations in order from least to greatest based on their solution.

Equation A: [tex] 5(x-6)+3x = \frac{3}{4}(2x-8) [/tex]

Equation B: [tex] 2.7(5.1x+4.9) = 3.2x + 28.9 [/tex]

Equation C: [tex] 5(11x-18) = 3(2x+7) [/tex]

[tex] \square \ \textless \ \square \ \textless \ \square [/tex]



Answer :

Given the three equations, let's determine their solutions and then arrange them in order from least to greatest.

Equation A:
[tex]\[ 5(x - 6) + 3x = \frac{3}{4}(2x - 8) \][/tex]

Equation B:
[tex]\[ 2.7(5.1x + 4.9) = 3.2x + 28.9 \][/tex]

Equation C:
[tex]\[ 5(11x - 18) = 3(2x + 7) \][/tex]

The solutions to these equations are:
- Solution for Equation A: [tex]\( x = 3.69230769230769 \)[/tex]
- Solution for Equation B: [tex]\( x = 1.48249763481552 \)[/tex]
- Solution for Equation C: [tex]\( x = \frac{111}{49} \approx 2.26530612244898 \)[/tex]

To arrange these solutions in order from least to greatest, we compare the numerical values:
- Equation B: [tex]\( x \approx 1.48249763481552 \)[/tex]
- Equation C: [tex]\( x \approx 2.26530612244898 \)[/tex]
- Equation A: [tex]\( x \approx 3.69230769230769 \)[/tex]

Thus, the order from least to greatest is:
[tex]\[ \text{Equation B} < \text{Equation C} < \text{Equation A} \][/tex]

So, the arrangement is:
[tex]\[ \boxed{\text{Equation B}} < \boxed{\text{Equation C}} < \boxed{\text{Equation A}} \][/tex]