What is the least common denominator of the rational expressions below?

[tex]\[ \frac{6}{x^2+7x} - \frac{8}{x^2+10x+21} \][/tex]

A. [tex]\( x+7 \)[/tex]

B. [tex]\( x(x+7)^2(x+3) \)[/tex]

C. [tex]\( x(x+7)(x+3) \)[/tex]

D. [tex]\( x(x+3) \)[/tex]



Answer :

To determine the least common denominator (LCD) of the given rational expressions, let's first factor their denominators step-by-step.

### Step 1: Factor the Denominators

1. First Denominator: [tex]\(x^2 + 7x\)[/tex]

To factor this polynomial, we can factor out the greatest common factor (GCF):
[tex]\[ x^2 + 7x = x(x + 7) \][/tex]

2. Second Denominator: [tex]\(x^2 + 10x + 21\)[/tex]

We need to find two numbers that multiply to 21 and add to 10. The numbers 3 and 7 satisfy this:
[tex]\[ x^2 + 10x + 21 = (x + 3)(x + 7) \][/tex]

### Step 2: Least Common Denominator (LCD)

To find the LCD, we need to find a common denominator that includes all the factors of both denominators.

- From the first denominator [tex]\(x(x + 7)\)[/tex]:
[tex]\[ \text{Factors: } x, (x + 7) \][/tex]

- From the second denominator [tex]\((x + 3)(x + 7)\)[/tex]:
[tex]\[ \text{Factors: } (x + 3), (x + 7) \][/tex]

### Step 3: Combine the Factors

To form the LCD, we take each distinct factor at its highest power:

- The factor [tex]\(x\)[/tex] appears once in the first denominator.
- The factor [tex]\(x + 7\)[/tex] appears once in both denominators.
- The factor [tex]\(x + 3\)[/tex] appears once in the second denominator.

Therefore, the least common denominator will have each of these factors, multiplied together:
[tex]\[ \text{LCD} = x \cdot (x + 7) \cdot (x + 3) \][/tex]

### Step 4: Verify the Answer
The LCD is:
[tex]\[ x(x + 7)(x + 3) \][/tex]

Thus, the correct answer is:
[tex]\[ \boxed{C. \, x(x + 7)(x + 3)} \][/tex]