What is the sum of the rational expressions below?

[tex]\[
\frac{3x}{x+9} + \frac{x}{x-4}
\][/tex]

A. [tex]\(\frac{4x^2 - 3x}{2x + 5}\)[/tex]

B. [tex]\(\frac{4x}{2x + 5}\)[/tex]

C. [tex]\(\frac{4x^2 - 3x}{x^2 + 5x - 36}\)[/tex]

D. [tex]\(\frac{4x}{x^2 + 5x - 36}\)[/tex]



Answer :

To find the sum of the rational expressions [tex]\(\frac{3x}{x+9} + \frac{x}{x-4}\)[/tex], we need to combine them into a single fraction. Here’s the step-by-step solution:

1. Identify the Least Common Denominator (LCD):

The denominators of the given expressions are [tex]\(x+9\)[/tex] and [tex]\(x-4\)[/tex]. The least common denominator (LCD) of these two denominators is [tex]\((x+9)(x-4)\)[/tex].

2. Rewrite each fraction with the LCD as the denominator:

For [tex]\(\frac{3x}{x+9}\)[/tex]:
[tex]\[ \frac{3x}{x+9} \cdot \frac{x-4}{x-4} = \frac{3x(x-4)}{(x+9)(x-4)} \][/tex]

For [tex]\(\frac{x}{x-4}\)[/tex]:
[tex]\[ \frac{x}{x-4} \cdot \frac{x+9}{x+9} = \frac{x(x+9)}{(x+9)(x-4)} \][/tex]

3. Combine the two fractions:

Now that both fractions have the same denominator, we can add the numerators:
[tex]\[ \frac{3x(x-4)}{(x+9)(x-4)} + \frac{x(x+9)}{(x+9)(x-4)} = \frac{3x(x-4) + x(x+9)}{(x+9)(x-4)} \][/tex]

4. Simplify the numerator:

Expand the expressions in the numerator:
[tex]\[ 3x(x-4) + x(x+9) = 3x^2 - 12x + x^2 + 9x = 4x^2 - 3x \][/tex]

5. Write the simplified combined fraction:

The result is:
[tex]\[ \frac{4x^2 - 3x}{(x+9)(x-4)} \][/tex]

Recognize that [tex]\((x+9)(x-4)\)[/tex] can be rewritten as [tex]\(x^2 + 5x - 36\)[/tex].

6. Final simplified expression:

Thus, the sum of the given rational expressions is:
[tex]\[ \frac{4x^2 - 3x}{x^2 + 5x - 36} \][/tex]

Therefore, the correct answer is:
[tex]\[ \boxed{\frac{4x^2-3x}{x^2+5x-36}} \][/tex]

So the correct option is [tex]\(C\)[/tex].

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