Answered

For each offspring genotype in the Punnett square you just completed, determine the phenotype. In other words, what is the predicted fur color and eye color of the offspring? Using your Punnett square from the last step, fill in the predicted fraction for each phenotype in the data table below.

\begin{tabular}{|l|c|c|c|c|}
\hline
& \begin{tabular}{c}
Black Fur and \\
Black Eyes
\end{tabular} & \begin{tabular}{c}
Black Fur and \\
Red Eyes
\end{tabular} & \begin{tabular}{c}
White Fur and \\
Black Eyes
\end{tabular} & \begin{tabular}{c}
White Fur and \\
Red Eyes
\end{tabular} \\
\hline
Predicted Fraction & [tex]$\square / 16$[/tex] & [tex]$\square / 16$[/tex] & [tex]$\square / 16$[/tex] & [tex]$\square / 16$[/tex] \\
\hline
\end{tabular}



Answer :

GinnyAnswer
To solve the problem, we need to use the information from a Punnett square for two traits: fur color and eye color. For simplicity, let’s assume the traits are controlled by two pairs of alleles:

1. Fur color: Black (B) is dominant over white (b).
2. Eye color: Black (E) is dominant over red (e).

We need the genotypes of the parents to complete the Punnett square. Let’s assume the parents are heterozygous for both traits: [tex]\( BbEe \times BbEe \)[/tex].

We can set up a 4x4 Punnett square to illustrate the combinations of these alleles:

[tex]\[ \begin{array}{c|cccc} & BE & Be & bE & be \\ \hline BE & BBEE & BBEe & BbEE & BbEe \\ Be & BBEe & BBee & BbEe & Bbee \\ bE & BbEE & BbEe & bbEE & bbEe \\ be & BbEe & Bbee & bbEe & bbee \\ \end{array} \][/tex]

Now let’s determine the phenotypes resulting from each genotype and count their occurrences:

1. Black Fur and Black Eyes (BBEE, BBEe, BbEE, BbEe):
- [tex]\( BBEE \)[/tex]: 1
- [tex]\( BBEe \)[/tex]: 2
- [tex]\( BbEE \)[/tex]: 2
- [tex]\( BbEe \)[/tex]: 4
- Total: 9

2. Black Fur and Red Eyes (BBee, Bbee):
- [tex]\( BBee \)[/tex]: 1
- [tex]\( Bbee \)[/tex]: 2
- Total: 3

3. White Fur and Black Eyes (bbEE, bbEe):
- [tex]\( bbEE \)[/tex]: 1
- [tex]\( bbEe \)[/tex]: 2
- Total: 3

4. White Fur and Red Eyes (bbee):
- [tex]\( bbee \)[/tex]: 1

To fill in the predicted fractions for each phenotype in the data table, we consider the total number of offspring combinations in the Punnett square, which is 16:

[tex]\[ \begin{array}{|l|c|c|c|c|c|} \cline{2-6} \multicolumn{1}{c|}{} & \begin{tabular}{c} Black Fur and \\ Black Eyes \end{tabular} & \begin{tabular}{c} Black Fur and \\ Red Eyes \end{tabular} & \begin{tabular}{c} White Fur and \\ Black Eyes \end{tabular} & \begin{tabular}{c} White Fur and \\ Red Eyes \end{tabular} \\ \hline Predicted Fraction & \frac{9}{16} & \frac{3}{16} & \frac{3}{16} & \frac{1}{16} \\ \hline \end{array} \][/tex]

So, the completed data table with predicted fractions for each phenotype is as follows:
[tex]\[ \begin{tabular}{|l|c|c|c|c|} \cline { 2 - 5 } \multicolumn{1}{c|}{} & \begin{tabular}{c} Black Fur and \\ Black Eyes \end{tabular} & \begin{tabular}{c} Black Fur and \\ Red Eyes \end{tabular} & \begin{tabular}{c} White Fur and \\ Black Eyes \end{tabular} & \begin{tabular}{c} White Fur and \\ Red Eyes \end{tabular} \\ \hline Predicted Fraction & \frac{9}{16} & \frac{3}{16} & \frac{3}{16} & \frac{1}{16} \\ \hline \end{tabular} \][/tex]