The post office is at the corner of First Street and Main Street, which forms a right angle. First Street intersects with Oak Street to the north, and Main Street intersects with Oak Street to the east. The intersection of Main Street and Oak Street forms a [tex]y^{\circ}[/tex] angle, and [tex]\tan y^{\circ} = \frac{5}{7}[/tex]. Car A drives on Main Street for 14 miles to arrive at Oak Street. How far will car B have to travel on First Street to get to Oak Street? Round your answer to the nearest tenth of a mile.

A. 5 miles
B. 7.4 miles
C. 10 miles
D. 19.6 miles



Answer :

To determine how far Car B has to travel on First Street to reach Oak Street, let's proceed with a detailed solution, step by step.

1. Understanding Given Information:
- Given [tex]\( \tan y = \frac{5}{7} \)[/tex].
- Car A drives 14 miles on Main Street to arrive at Oak Street.

2. Recall the Tangent Function:
- The tangent of an angle in a right triangle is the ratio of the length of the opposite side to the adjacent side:
[tex]\[ \tan y = \frac{\text{opposite}}{\text{adjacent}} \][/tex]
- For this problem:
[tex]\[ \tan y = \frac{\text{distance on First Street}}{\text{distance on Main Street}} \][/tex]

3. Relate It to Given Values:
- Distance on Main Street (adjacent side) = 14 miles
- Distance on First Street (opposite side) = [tex]\( D \)[/tex] miles

4. Set Up the Equation Using Tangent:
[tex]\[ \frac{D}{14} = \frac{5}{7} \][/tex]

5. Solve for [tex]\( D \)[/tex]:
- Cross-multiply to solve for [tex]\( D \)[/tex]:
[tex]\[ D = 14 \times \frac{5}{7} \][/tex]
- Simplify:
[tex]\[ D = 14 \times 0.7142857 = 10.0 \][/tex]

6. Round to the Nearest Tenth:
- We have already reached a value that is to the nearest tenth, which is 10.0 miles.

7. Conclusion:
- Car B will have to travel [tex]\( 10.0 \)[/tex] miles on First Street to reach Oak Street.

Therefore, the distance that Car B has to travel on First Street to get to Oak Street is 10 miles.