To identify the products in the reaction [tex]\( HCl + NaOH \rightarrow NaCl + H_2O \)[/tex], we can analyze the reactants and products involved in this chemical equation. This reaction is a type of neutralization reaction where an acid reacts with a base to form a salt and water.
1. Identify Reactants:
- HCl (Hydrochloric acid)
- NaOH (Sodium hydroxide)
2. Identify Products:
When hydrochloric acid reacts with sodium hydroxide, they react to form:
- NaCl (Sodium chloride), which is the salt formed.
- [tex]\( H_2O \)[/tex] (Water)
3. Confirming the Reaction:
The reaction [tex]\( HCl + NaOH \rightarrow NaCl + H_2O \)[/tex] showcases that the hydrogen ion (H[tex]\(^+\)[/tex]) from HCl and the hydroxide ion (OH[tex]\(^-\)[/tex]) from NaOH combine to form water ([tex]\( H_2O \)[/tex]). Simultaneously, the remaining ions [tex]\( Na^+\)[/tex] and [tex]\( Cl^-\)[/tex] combine to form sodium chloride (NaCl).
Thus, the products of the reaction are:
A. NaCl and [tex]\( H_2O \)[/tex]
Hence, the correct answer is:
A. NaCl and [tex]\( H _2 O \)[/tex]
