Answer :
To find the y-intercept of the quadratic function [tex]\( f(x) = 5(x - 2)^2 - 8 \)[/tex], we need to determine the value of the function when [tex]\( x = 0 \)[/tex].
1. Substitute [tex]\( x = 0 \)[/tex] into the function:
[tex]\[ f(0) = 5(0 - 2)^2 - 8 \][/tex]
2. Simplify inside the parentheses:
[tex]\[ 0 - 2 = -2 \][/tex]
3. Square the result:
[tex]\[ (-2)^2 = 4 \][/tex]
4. Multiply by 5:
[tex]\[ 5 \cdot 4 = 20 \][/tex]
5. Subtract 8:
[tex]\[ 20 - 8 = 12 \][/tex]
Therefore, the y-intercept of the function is 12.
The correct answer is:
(2) 12
1. Substitute [tex]\( x = 0 \)[/tex] into the function:
[tex]\[ f(0) = 5(0 - 2)^2 - 8 \][/tex]
2. Simplify inside the parentheses:
[tex]\[ 0 - 2 = -2 \][/tex]
3. Square the result:
[tex]\[ (-2)^2 = 4 \][/tex]
4. Multiply by 5:
[tex]\[ 5 \cdot 4 = 20 \][/tex]
5. Subtract 8:
[tex]\[ 20 - 8 = 12 \][/tex]
Therefore, the y-intercept of the function is 12.
The correct answer is:
(2) 12