Answer :
Absolutely! Let's solve the problem step-by-step using the G-R-E-S-A method (Given, Required, Equation, Solution, Answer).
### Problem 1:
Given:
A boy and a girl each pull a heavy crate at the same time with 7 units of force.
Required:
To find the net force acting on the object and to determine if the object is balanced or unbalanced.
Equation:
Net force = Force exerted by the boy + Force exerted by the girl (since they are pulling in the same direction).
Solution:
[tex]\( \text{Net force} = 7 \, \text{units} + 7 \, \text{units} \)[/tex]
Answer:
The net force acting on the object is 14 units. Since the forces are in the same direction and their magnitudes add up, the object is unbalanced.
### Problem 2:
Given:
The boy pulls the heavy crate with a force of 20 units, and the girl pulls it with a force of 10 units, but in the opposite direction.
Required:
To find the net force acting on the object, and the direction in which it will move.
Equation:
Net force = Force exerted by the boy - Force exerted by the girl (since they are pulling in opposite directions).
Solution:
[tex]\( \text{Net force} = 20 \, \text{units} - 10 \, \text{units} \)[/tex]
Answer:
The net force acting on the object is 10 units in the direction of the boy's force. Hence, the object will move in the direction of the boy's pull.
### Problem 3:
Given:
A boy pulls the heavy crate with 20 units of force. One girl pulls with 10 units of force in the opposite direction. Another girl pulls with 10 units of force in the same direction as the first girl.
Required:
To find the net force acting on the object and to determine if the object will move.
Equation:
Net force = Force exerted by the boy - (Force exerted by the first girl + additional force by the second girl).
Solution:
[tex]\( \text{Net force} = 20 \, \text{units} - (10 \, \text{units} + 10 \, \text{units}) \)[/tex]
Answer:
The net force acting on the object is 0 units. Since the opposing forces balance each other out, the object will not move, meaning it remains balanced.
In summary:
1. Net Force = 14 units, unbalanced.
2. Net Force = 10 units, moves in the direction of the boy's pull.
3. Net Force = 0 units, balanced.
### Problem 1:
Given:
A boy and a girl each pull a heavy crate at the same time with 7 units of force.
Required:
To find the net force acting on the object and to determine if the object is balanced or unbalanced.
Equation:
Net force = Force exerted by the boy + Force exerted by the girl (since they are pulling in the same direction).
Solution:
[tex]\( \text{Net force} = 7 \, \text{units} + 7 \, \text{units} \)[/tex]
Answer:
The net force acting on the object is 14 units. Since the forces are in the same direction and their magnitudes add up, the object is unbalanced.
### Problem 2:
Given:
The boy pulls the heavy crate with a force of 20 units, and the girl pulls it with a force of 10 units, but in the opposite direction.
Required:
To find the net force acting on the object, and the direction in which it will move.
Equation:
Net force = Force exerted by the boy - Force exerted by the girl (since they are pulling in opposite directions).
Solution:
[tex]\( \text{Net force} = 20 \, \text{units} - 10 \, \text{units} \)[/tex]
Answer:
The net force acting on the object is 10 units in the direction of the boy's force. Hence, the object will move in the direction of the boy's pull.
### Problem 3:
Given:
A boy pulls the heavy crate with 20 units of force. One girl pulls with 10 units of force in the opposite direction. Another girl pulls with 10 units of force in the same direction as the first girl.
Required:
To find the net force acting on the object and to determine if the object will move.
Equation:
Net force = Force exerted by the boy - (Force exerted by the first girl + additional force by the second girl).
Solution:
[tex]\( \text{Net force} = 20 \, \text{units} - (10 \, \text{units} + 10 \, \text{units}) \)[/tex]
Answer:
The net force acting on the object is 0 units. Since the opposing forces balance each other out, the object will not move, meaning it remains balanced.
In summary:
1. Net Force = 14 units, unbalanced.
2. Net Force = 10 units, moves in the direction of the boy's pull.
3. Net Force = 0 units, balanced.