For the following set of data, find the population standard deviation to the nearest thousandth.

\begin{tabular}{|c|c|}
\hline
Data & Frequency \\
\hline
12 & 9 \\
\hline
13 & 4 \\
\hline
14 & 6 \\
\hline
25 & 8 \\
\hline
33 & 3 \\
\hline
34 & 4 \\
\hline
36 & 2 \\
\hline
\end{tabular}



Answer :

Let's solve the problem of finding the population standard deviation for the given dataset using a step-by-step approach.

### Step 1: Calculate the total number of data points

The total number of data points, [tex]\(N\)[/tex], is the sum of all the frequencies:
[tex]\[ N = 9 + 4 + 6 + 8 + 3 + 4 + 2 = 36 \][/tex]

### Step 2: Calculate the weighted mean

The weighted mean [tex]\(\mu\)[/tex] is found by taking the sum of each data point multiplied by its frequency, and then dividing by the total number of data points:

[tex]\[ \mu = \frac{\sum (x_i \cdot f_i)}{N} \][/tex]
where [tex]\(x_i\)[/tex] is the data point and [tex]\(f_i\)[/tex] is the frequency.

The sum of the data points multiplied by their frequencies is:
[tex]\[ \sum (x_i \cdot f_i) = (12 \cdot 9) + (13 \cdot 4) + (14 \cdot 6) + (25 \cdot 8) + (33 \cdot 3) + (34 \cdot 4) + (36 \cdot 2) = 751 \][/tex]

So, the weighted mean [tex]\(\mu\)[/tex] is:
[tex]\[ \mu = \frac{751}{36} \approx 20.861 \][/tex]

### Step 3: Calculate the variance

The variance [tex]\(\sigma^2\)[/tex] is found by taking the sum of the squared differences between each data point and the mean, multiplied by their frequencies, and then dividing by the total number of data points:
[tex]\[ \sigma^2 = \frac{\sum [f_i \cdot (x_i - \mu)^2]}{N} \][/tex]

The sum of the squared differences multiplied by frequencies is:
[tex]\[ \sum [f_i \cdot (x_i - \mu)^2] = (9 \cdot (12 - 20.861)^2) + (4 \cdot (13 - 20.861)^2) + (6 \cdot (14 - 20.861)^2) + (8 \cdot (25 - 20.861)^2) + (3 \cdot (33 - 20.861)^2) + (4 \cdot (34 - 20.861)^2) + (2 \cdot (36 - 20.861)^2) = 2964.306 \][/tex]

So, the variance [tex]\(\sigma^2\)[/tex] is:
[tex]\[ \sigma^2 = \frac{2964.306}{36} \approx 82.342 \][/tex]

### Step 4: Calculate the population standard deviation

The population standard deviation [tex]\(\sigma\)[/tex] is the square root of the variance:
[tex]\[ \sigma = \sqrt{82.342} \approx 9.074 \][/tex]

Therefore, the population standard deviation for the given set of data, rounded to the nearest thousandth, is:
[tex]\[ \sigma \approx 9.074 \][/tex]