The probability for event A is 0.4, the probability for event B is 0.2, and the probability of events A and B is 0.1.

Why are the events not independent?

A. The sum of [tex]P(A)[/tex] and [tex]P(B)[/tex] is greater than [tex]P(A \text{ and } B)[/tex].
B. The product of [tex]P(A)[/tex] and [tex]P(B)[/tex] is greater than [tex]P(A \text{ and } B)[/tex].
C. The product of [tex]P(A)[/tex] and [tex]P(B)[/tex] is not equal to [tex]P(A \text{ and } B)[/tex].
D. The sum of [tex]P(A)[/tex] and [tex]P(B)[/tex] is not equal to [tex]P(A \text{ and } B)[/tex].



Answer :

To determine whether two events, A and B, are independent, we must check if the product of their individual probabilities [tex]\(P(A)\)[/tex] and [tex]\(P(B)\)[/tex] is equal to the probability of both events occurring together, which is [tex]\(P(A \cap B)\)[/tex].

Given:
- [tex]\(P(A) = 0.4\)[/tex]
- [tex]\(P(B) = 0.2\)[/tex]
- [tex]\(P(A \cap B) = 0.1\)[/tex]

Step-by-step solution:

1. Calculate the product of [tex]\(P(A)\)[/tex] and [tex]\(P(B)\)[/tex]:
[tex]\[ P(A) \times P(B) = 0.4 \times 0.2 = 0.08 \][/tex]

2. Compare the product [tex]\(P(A) \times P(B)\)[/tex] to [tex]\(P(A \cap B)\)[/tex]:
[tex]\[ P(A \times B) = 0.08 \][/tex]
[tex]\[ P(A \cap B) = 0.1 \][/tex]

Since [tex]\(P(A) \times P(B)\)[/tex] equals 0.08 and [tex]\(P(A \cap B)\)[/tex] equals 0.1, we notice that:

[tex]\[ P(A) \times P(B) \neq P(A \cap B) \][/tex]

Therefore, the reason the events A and B are not independent is that the product of [tex]\(P(A)\)[/tex] and [tex]\(P(B)\)[/tex] is not equal to [tex]\(P(A \cap B)\)[/tex].

Hence, the correct answer is:
- The product of [tex]\(P(A)\)[/tex] and [tex]\(P(B)\)[/tex] is not equal to [tex]\(P(A \cap B)\)[/tex].