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Complete the paragraph to describe the relationship between kinetic energy and braking distance. Use [tex]$KE = \frac{1}{2} mv^2$[/tex].

A car moves at a speed of 50 kilometers/hour. Its kinetic energy is 400 joules. If the same car moves at a speed of 100 kilometers/hour, then its kinetic energy will be [tex] \square [/tex] joules. The braking distance at the faster speed is [tex] \square [/tex] the braking distance at the slower speed.



Answer :

A car moves at a speed of 50 kilometers/hour. Its kinetic energy is 400 joules. If the same car moves at a speed of 100 kilometers/hour, then its kinetic energy will be 1600 joules. The braking distance at the faster speed is 4 times the braking distance at the slower speed.