Solve the following expressions using PEMDAS (Parentheses, Exponents, Multiplication and Division, Addition and Subtraction):

1. [tex]1.4 \times (15 - 13) + 16[/tex]

2. [tex](93 + 7) \times 6 + 10[/tex]

3. [tex]12 \times 3 + \left(\frac{100}{10}\right)[/tex]



Answer :

Certainly! Let's solve each of the given expressions step-by-step, using the rules for the order of operations (PEMDAS/BODMAS).

### 1. [tex]\(1.4 \times (15 - 13) + 16\)[/tex]

1. Start by solving the expression inside the parentheses:
[tex]\[ 15 - 13 = 2 \][/tex]

2. Next, multiply the result by 1.4:
[tex]\[ 1.4 \times 2 = 2.8 \][/tex]

3. Finally, add 16 to the result:
[tex]\[ 2.8 + 16 = 18.8 \][/tex]

So, the final result is:
[tex]\[ 18.8 \][/tex]

### 2. [tex]\((93 + 7) \times 6 + 10\)[/tex]

1. Start by solving the expression inside the parentheses:
[tex]\[ 93 + 7 = 100 \][/tex]

2. Next, multiply the result by 6:
[tex]\[ 100 \times 6 = 600 \][/tex]

3. Finally, add 10 to the result:
[tex]\[ 600 + 10 = 610 \][/tex]

So, the final result is:
[tex]\[ 610 \][/tex]

### 3. [tex]\(12 \times 3 + (100 \div 10)\)[/tex]

1. Start by solving the division inside the parentheses:
[tex]\[ 100 \div 10 = 10 \][/tex]

2. Next, multiply 12 by 3:
[tex]\[ 12 \times 3 = 36 \][/tex]

3. Finally, add the results:
[tex]\[ 36 + 10 = 46 \][/tex]

So, the final result is:
[tex]\[ 46 \][/tex]

To summarize, the solutions to the given problems are:
1. [tex]\(1.4 \times (15 - 13) + 16 = 18.8\)[/tex]
2. [tex]\((93 + 7) \times 6 + 10 = 610\)[/tex]
3. [tex]\(12 \times 3 + (100 \div 10) = 46\)[/tex]