The line [tex]$y=kx+4$[/tex] is graphed in the [tex]$xy$[/tex]-plane. Express the point [tex][tex]$(c, d)$[/tex][/tex], where [tex]$c \neq 0$[/tex], in terms of [tex]c[/tex] and [tex]k[/tex].



Answer :

Certainly! Let's walk through the problem step-by-step to find the value of [tex]\( k \)[/tex].

1. Understand the Problem: We are given the equation of a line [tex]\( y = kx + 4 \)[/tex]. We also know that the point [tex]\((c, d)\)[/tex] lies on this line. Our goal is to express the slope [tex]\( k \)[/tex] in terms of [tex]\( c \)[/tex] and [tex]\( d \)[/tex].

2. Point-Slope Relationship: Since the point [tex]\((c, d)\)[/tex] lies on the line [tex]\( y = kx + 4 \)[/tex], we know that when [tex]\( x = c \)[/tex], [tex]\( y = d \)[/tex]. This gives us the relationship to work with:

[tex]\[ d = kc + 4 \][/tex]

3. Solving for [tex]\( k \)[/tex]: We need to isolate [tex]\( k \)[/tex] in the equation. Start by subtracting 4 from both sides of the equation:

[tex]\[ d - 4 = kc \][/tex]

4. Isolate [tex]\( k \)[/tex]: Now solve for [tex]\( k \)[/tex] by dividing both sides by [tex]\( c \)[/tex]:

[tex]\[ k = \frac{d - 4}{c} \][/tex]

So the slope [tex]\( k \)[/tex] of the line in terms of [tex]\( c \)[/tex] and [tex]\( d \)[/tex] is:

[tex]\[ k = \frac{d - 4}{c} \][/tex]

This is the required expression for [tex]\( k \)[/tex].