A 95 kg man lying on a surface of negligible friction shoves an 85 g stone away from himself, giving it a speed of 3.7 m/s. What speed does the man acquire as a result?



Answer :

Answer:

The man is given an acceleration of 0.003 m/s² as a result of him pushing the stone.

Explanation:

Newton's Third Law of Motion states that for every action, there is an equal and opposite reaction. When the man pushes the stone away from himself, the stone also pushes him away from it with the same amount of force.

We need to know the amount of force the man used to push the stone. Newton's Second Law of Motion states that the amount of acceleration is proportional to the amount of force, with the constant of proportionality being the object's mass. The equation for this is F = ma, where -

- F is force in Newtons (N)

- m is mass in kilograms (kg)

- a is acceleration in meters/second² (m/s²)

We can use this equation to find the amount of force the man used. The stone weighs 85g (or 0.085 kilograms) and had an acceleration of 3.7 m/s². Plugging these in gives us -

F = 0.085 * 3.7 = 0.3145 N

The man pushed the stone with 0.3145 N, so the stone pushes him with 0.3145 N as well. We can plug that into the equation to find the man's acceleration.

0.3145 = 95a

0.003 m/s² = a