Solve for [tex]$x$[/tex]:

[tex]\frac{x}{2} \geq -4[/tex]

A. [tex]x \geq -8[/tex]

B. [tex]x \leq -2[/tex]

C. [tex]x \leq -8[/tex]

D. [tex]x \geq -2[/tex]



Answer :

Certainly! Let's solve the inequality step by step.

Step 1: Solve the given inequality

Given:
[tex]\[ \frac{x}{2} \geq -4 \][/tex]

We need to isolate [tex]\(x\)[/tex]. To do this, multiply both sides by 2:
[tex]\[ x \geq -4 \times 2 \][/tex]
[tex]\[ x \geq -8 \][/tex]

Step 2: Given inequalities

We also have the inequalities given:
[tex]\[ x \geq -8 \][/tex]
[tex]\[ x \leq -2 \][/tex]

We need to find the values of [tex]\(x\)[/tex] that satisfy both inequalities simultaneously.

Step 3: Combine the inequalities

The combined inequality is:
[tex]\[ -8 \leq x \leq -2 \][/tex]

This combined inequality means that [tex]\(x\)[/tex] must be greater than or equal to -8 and less than or equal to -2.

Step 4: Conclusion

After considering both inequalities, the solution for [tex]\(x\)[/tex] is:
[tex]\[ -8 \leq x \leq -2 \][/tex]

In interval notation, the solution can be written as:
[tex]\[ [-8, -2] \][/tex]

This means that [tex]\(x\)[/tex] can take any value between -8 and -2, inclusive.