Which equation represents a line that passes through [tex]\left(4, \frac{1}{3}\right)[/tex] and has a slope of [tex]\frac{3}{4}[/tex]?

A. [tex]y-\frac{3}{4}=\frac{1}{3}(x-4)[/tex]
B. [tex]y-\frac{1}{3}=\frac{3}{4}(x-4)[/tex]
C. [tex]y-\frac{1}{3}=4\left(x-\frac{3}{4}\right)[/tex]
D. [tex]y-4=\frac{3}{4}\left(x-\frac{1}{3}\right)[/tex]



Answer :

To determine which equation represents a line that passes through the point [tex]\(\left(4, \frac{1}{3}\right)\)[/tex] and has a slope of [tex]\(\frac{3}{4}\)[/tex], we can use the point-slope form of a linear equation.

The point-slope form of a line is given by:

[tex]\[ y - y_1 = m(x - x_1) \][/tex]

Where:
- [tex]\((x_1, y_1)\)[/tex] is a point on the line
- [tex]\(m\)[/tex] is the slope of the line

Given:
[tex]\[ (x_1, y_1) = \left(4, \frac{1}{3}\right) \][/tex]
[tex]\[ m = \frac{3}{4} \][/tex]

Substituting the given point and slope into the point-slope form, we get:

[tex]\[ y - \frac{1}{3} = \frac{3}{4}(x - 4) \][/tex]

This equation matches the second option provided:
[tex]\[ y - \frac{1}{3} = \frac{3}{4}(x - 4) \][/tex]

Therefore, the correct equation representing the line that passes through [tex]\(\left(4, \frac{1}{3}\right)\)[/tex] with a slope of [tex]\(\frac{3}{4}\)[/tex] is:

[tex]\[ \boxed{y-\frac{1}{3}=\frac{3}{4}(x-4)} \][/tex]