Answered

What is the domain of this square root function?

[tex]\[
f(x) = \sqrt{x + 4} - 17
\][/tex]

[tex]\[
x \geq [?]
\][/tex]



Answer :

To determine the domain of the function [tex]\( f(x) = \sqrt{x+4} - 17 \)[/tex], we need to ensure that the expression inside the square root is non-negative. This is important because the square root of a negative number is not defined in the set of real numbers.

Let's break it down step by step:

1. Identify the expression inside the square root:
[tex]\[ \sqrt{x+4} \][/tex]

2. Set the argument of the square root to be non-negative:
[tex]\[ x + 4 \geq 0 \][/tex]

3. Solve this inequality:
[tex]\[ x + 4 \geq 0 \][/tex]
Subtract 4 from both sides:
[tex]\[ x \geq -4 \][/tex]

Therefore, the domain of the function [tex]\( f(x) = \sqrt{x+4} - 17 \)[/tex] is all [tex]\( x \)[/tex] such that [tex]\( x \geq -4 \)[/tex].

In interval notation, this is expressed as:
[tex]\[ [-4, \infty) \][/tex]

So, the domain of the function is [tex]\( x \geq -4 \)[/tex].