Let's solve the given system of equations step by step:
Equation 1:
[tex]\[ 3x + 5 = 26 \][/tex]
1. Subtract 5 from both sides to isolate the term involving [tex]\(x\)[/tex]:
[tex]\[ 3x + 5 - 5 = 26 - 5 \][/tex]
[tex]\[ 3x = 21 \][/tex]
2. Divide both sides by 3 to solve for [tex]\(x\)[/tex]:
[tex]\[ x = \frac{21}{3} \][/tex]
[tex]\[ x = 7 \][/tex]
Equation 2:
[tex]\[ 6x - 5 = 19 \][/tex]
1. Add 5 to both sides to isolate the term involving [tex]\(x\)[/tex]:
[tex]\[ 6x - 5 + 5 = 19 + 5 \][/tex]
[tex]\[ 6x = 24 \][/tex]
2. Divide both sides by 6 to solve for [tex]\(x\)[/tex]:
[tex]\[ x = \frac{24}{6} \][/tex]
[tex]\[ x = 4 \][/tex]
So, we find that from the first equation, [tex]\(x = 7\)[/tex] and from the second equation, [tex]\(x = 4\)[/tex].
