A spinner is spun twice with 4 equal sections colored purple, red, green, and blue. What is the theoretical probability of landing on purple both times?

A. [tex]$\frac{1}{4}$[/tex]
B. [tex]$\frac{1}{6}$[/tex]
C. [tex]$\frac{1}{8}$[/tex]
D. [tex]$\frac{1}{16}$[/tex]



Answer :

Let's analyze the given problem step-by-step.

1. Understanding the Problem:
- We have a spinner with 4 equal sections.
- The sections are colored purple, red, green, and blue.
- The spinner is spun twice.
- We want to find the probability of landing on a specific color in both spins.

2. Step-by-Step Calculation:
- First, determine the probability of landing on a specific color in a single spin. Since there are 4 equal sections, the probability of landing on any specific color (like purple) in one spin is:
[tex]\[ \text{Probability in one spin} = \frac{1}{4} \][/tex]

- Next, we need to find the combined probability for two spins. The events (spins) are independent, so the combined probability of landing on a specific color in both spins is obtained by multiplying the probabilities of each individual spin:
[tex]\[ \text{Combined Probability} = \left(\frac{1}{4}\right) \times \left(\frac{1}{4}\right) \][/tex]

- Simplifying this, we get:
[tex]\[ \left(\frac{1}{4}\right) \times \left(\frac{1}{4}\right) = \frac{1}{16} \][/tex]

3. Conclusion:
- The probability of landing on a specific color in both spins is [tex]\(\frac{1}{16}\)[/tex].

Therefore, the correct answer is [tex]\(\frac{1}{16}\)[/tex].