Rammy has [tex]$\$[/tex]9.60[tex]$ to spend on some peaches and a gallon of milk. Peaches cost $[/tex]\[tex]$1.20$[/tex] per pound, and a gallon of milk costs [tex]$\$[/tex]3.60[tex]$.

The inequality $[/tex]1.20x + 3.60 \leq 9.60[tex]$ models this situation, where $[/tex]x[tex]$ is the number of pounds of peaches.

Solve the inequality. How many pounds of peaches can Rammy buy?

A. $[/tex]x \geq 5[tex]$; Rammy can buy 5 pounds or more of peaches.
B. $[/tex]x \leq 8[tex]$; Rammy can buy 8 pounds or less of peaches.
C. $[/tex]x \leq 5[tex]$; Rammy can buy 5 pounds or less of peaches.
D. $[/tex]x \geq 8$; Rammy can buy 8 pounds or more of peaches.



Answer :

To determine how many pounds of peaches Rammy can buy within his budget of [tex]$9.60, we need to solve the given inequality: \[ 1.20x + 3.60 \leq 9.60 \] Let’s solve this step-by-step: 1. Isolate the term involving \( x \): Start by subtracting the cost of the milk ($[/tex]3.60) from both sides of the inequality to isolate the term involving the peaches:

[tex]\[ 1.20x + 3.60 - 3.60 \leq 9.60 - 3.60 \][/tex]

Simplifies to:

[tex]\[ 1.20x \leq 6.00 \][/tex]

2. Solve for [tex]\( x \)[/tex]:
Next, divide both sides by the coefficient of [tex]\( x \)[/tex] (which is $1.20) to solve for [tex]\( x \)[/tex]:

[tex]\[ x \leq \frac{6.00}{1.20} \][/tex]

Simplifies to:

[tex]\[ x \leq 5 \][/tex]

Therefore, Rammy can buy 5 pounds or less of peaches. The number of pounds of peaches Rammy can buy is represented by option C.

So, the correct answer is:

C. [tex]\( x \leq 5 \)[/tex]; Rammy can buy 5 pounds or less of peaches.