Select the correct answer.

The dimensions and number of animals are given for different corrals.
\begin{tabular}{|l|l|l|l|}
\hline \multicolumn{1}{|c|}{ Corral } & \multicolumn{1}{|c|}{ Length } & \multicolumn{1}{|c|}{ Width } & Number of Animals \\
\hline 1 & 50 meters & 40 meters & 110 \\
\hline 2 & 60 meters & 35 meters & 115 \\
\hline 3 & 55 meters & 45 meters & 125 \\
\hline 4 & 65 meters & 40 meters & 130 \\
\hline
\end{tabular}

The population constraints state that each corral should have at least 20 square meters for each animal. Which corral meets this requirement?

A. Corral 1
B. Corral 2
C. Corral 3
D. Corral 4



Answer :

Sure, let's evaluate each corral step by step to see if it meets the requirement of having at least 20 square meters per animal.

First, we will calculate the area of each corral by multiplying the length and the width.

1. Corral 1:
- Length: 50 meters
- Width: 40 meters
- Area: [tex]\( 50 \times 40 = 2000 \)[/tex] square meters
- Number of animals: 110
- Area per animal: [tex]\( \frac{2000}{110} \approx 18.18 \)[/tex] square meters per animal

Since 18.18 is less than 20, Corral 1 does not meet the requirement.

2. Corral 2:
- Length: 60 meters
- Width: 35 meters
- Area: [tex]\( 60 \times 35 = 2100 \)[/tex] square meters
- Number of animals: 115
- Area per animal: [tex]\( \frac{2100}{115} \approx 18.26 \)[/tex] square meters per animal

Since 18.26 is less than 20, Corral 2 does not meet the requirement.

3. Corral 3:
- Length: 55 meters
- Width: 45 meters
- Area: [tex]\( 55 \times 45 = 2475 \)[/tex] square meters
- Number of animals: 125
- Area per animal: [tex]\( \frac{2475}{125} = 19.8 \)[/tex] square meters per animal

Since 19.8 is less than 20, Corral 3 does not meet the requirement.

4. Corral 4:
- Length: 65 meters
- Width: 40 meters
- Area: [tex]\( 65 \times 40 = 2600 \)[/tex] square meters
- Number of animals: 130
- Area per animal: [tex]\( \frac{2600}{130} = 20 \)[/tex] square meters per animal

Since 20 is equal to 20, Corral 4 does meet the requirement.

Therefore, the correct answer is:

D. Corral 4