PYRAMIDS

The surface area [tex]S[/tex] of a right pyramid is given by [tex]S=\frac{1}{2} P \ell + B[/tex], where [tex]P[/tex] is the perimeter of the base, [tex]\ell[/tex] is the slant height, and [tex]B[/tex] is the area of the base.

Solve for [tex]\ell[/tex].



Answer :

Certainly! Let's solve for the slant height [tex]\( \ell \)[/tex] in the given formula for the surface area [tex]\( S \)[/tex] of a right pyramid:

The formula given for the surface area [tex]\( S \)[/tex] is:
[tex]\[ S = \frac{1}{2} P \ell + B, \][/tex]
where:
- [tex]\( S \)[/tex] is the surface area,
- [tex]\( P \)[/tex] is the perimeter of the base,
- [tex]\( \ell \)[/tex] is the slant height,
- [tex]\( B \)[/tex] is the area of the base.

We need to solve this formula for [tex]\( \ell \)[/tex].

Step-by-Step Solution:

1. Isolate the term with [tex]\( \ell \)[/tex]:

Start by isolating the term containing [tex]\( \ell \)[/tex] on one side of the equation.
[tex]\[ S - B = \frac{1}{2} P \ell. \][/tex]

2. Eliminate the fraction:

To eliminate the fraction, multiply both sides of the equation by 2.
[tex]\[ 2(S - B) = P \ell. \][/tex]

3. Solve for [tex]\( \ell \)[/tex]:

Finally, solve for [tex]\( \ell \)[/tex] by dividing both sides of the equation by [tex]\( P \)[/tex].
[tex]\[ \ell = \frac{2(S - B)}{P}. \][/tex]

So, the slant height [tex]\( \ell \)[/tex] in terms of the surface area [tex]\( S \)[/tex], the perimeter of the base [tex]\( P \)[/tex], and the area of the base [tex]\( B \)[/tex] is:
[tex]\[ \ell = \frac{2(S - B)}{P}. \][/tex]

This formula allows you to find the slant height [tex]\( \ell \)[/tex] if you know the values of the surface area [tex]\( S \)[/tex], the perimeter of the base [tex]\( P \)[/tex], and the area of the base [tex]\( B \)[/tex].