Which of the following did you include in your description? Check all of the boxes that apply.

1. Let [tex] x [/tex] be the smallest even integer, [tex] x+2 [/tex] be the next even integer, and [tex] x+4 [/tex] be the largest even integer.
2. Write the equation [tex] x + (x+2) + (x+4) = -78 [/tex].
3. Simplify the equation as [tex] 3x + 6 = -78 [/tex].
4. Solve the equation by subtracting 6 and dividing by 3 on both sides of the equation.
5. Check that the sum of the integers [tex] -28 [/tex], [tex] -26 [/tex], and [tex] -24 [/tex] is [tex] -78 [/tex].



Answer :

Let's solve this problem step by step:

1. Define the integers: Let [tex]\( x \)[/tex] be the smallest even integer. Then, the next even integer would be [tex]\( x + 2 \)[/tex], and the largest even integer would be [tex]\( x + 4 \)[/tex].

2. Write the equation: We know that the sum of these three integers equals -78. Therefore, we can write the equation:
[tex]\[ x + (x + 2) + (x + 4) = -78 \][/tex]

3. Simplify the equation: Combine like terms:
[tex]\[ x + x + 2 + x + 4 = -78 \][/tex]
[tex]\[ 3x + 6 = -78 \][/tex]

4. Solve the equation: To isolate [tex]\( x \)[/tex]:
[tex]\[ 3x + 6 = -78 \][/tex]
Subtract 6 from both sides:
[tex]\[ 3x = -78 - 6 \][/tex]
[tex]\[ 3x = -84 \][/tex]
Divide both sides by 3:
[tex]\[ x = -28 \][/tex]

5. Find the integers:
- The smallest even integer is [tex]\( x = -28 \)[/tex].
- The next even integer is [tex]\( x + 2 = -28 + 2 = -26 \)[/tex].
- The largest even integer is [tex]\( x + 4 = -28 + 4 = -24 \)[/tex].

6. Check the solution: Sum the integers to ensure they equal -78.
[tex]\[ -28 + (-26) + (-24) = -28 - 26 - 24 = -78 \][/tex]

Hence, the solution to the problem is that the smallest even integer is [tex]\(-28\)[/tex], the next even integer is [tex]\(-26\)[/tex], and the largest even integer is [tex]\(-24\)[/tex].