Which point is a solution to the equation [tex]y = (x-2)^2[/tex]?

A. [tex](3,1)[/tex]
B. [tex](4,0)[/tex]
C. [tex](1,-1)[/tex]
D. [tex](-3,1)[/tex]



Answer :

To determine which point among the given options is a solution to the equation [tex]\( y = (x - 2)^2 \)[/tex], we need to substitute each point into the equation and check if it holds true.

Let's consider each point one by one:

1. Point [tex]\((3, 1)\)[/tex]:
- Substitute [tex]\( x = 3 \)[/tex] and [tex]\( y = 1 \)[/tex] into the equation [tex]\( y = (x - 2)^2 \)[/tex]:
[tex]\[ y = (3 - 2)^2 = 1^2 = 1 \][/tex]
This is true since [tex]\( y = 1 \)[/tex]. Thus, the point [tex]\((3, 1)\)[/tex] satisfies the equation.

2. Point [tex]\((1, -1)\)[/tex]:
- Substitute [tex]\( x = 1 \)[/tex] and [tex]\( y = -1 \)[/tex] into the equation [tex]\( y = (x - 2)^2 \)[/tex]:
[tex]\[ y = (1 - 2)^2 = (-1)^2 = 1 \][/tex]
This is not true since [tex]\( y \neq -1 \)[/tex]. Thus, the point [tex]\((1, -1)\)[/tex] does not satisfy the equation.

3. Point [tex]\((4, 0)\)[/tex]:
- Substitute [tex]\( x = 4 \)[/tex] and [tex]\( y = 0 \)[/tex] into the equation [tex]\( y = (x - 2)^2 \)[/tex]:
[tex]\[ y = (4 - 2)^2 = 2^2 = 4 \][/tex]
This is not true since [tex]\( y \neq 0 \)[/tex]. Thus, the point [tex]\((4, 0)\)[/tex] does not satisfy the equation.

4. Point [tex]\((-3, 1)\)[/tex]:
- Substitute [tex]\( x = -3 \)[/tex] and [tex]\( y = 1 \)[/tex] into the equation [tex]\( y = (x - 2)^2 \)[/tex]:
[tex]\[ y = (-3 - 2)^2 = (-5)^2 = 25 \][/tex]
This is not true since [tex]\( y \neq 1 \)[/tex]. Thus, the point [tex]\((-3, 1)\)[/tex] does not satisfy the equation.

Having checked all points, the point [tex]\((3, 1)\)[/tex] is the only one that satisfies the equation [tex]\( y = (x - 2)^2 \)[/tex].

Thus, the answer is:
(A) [tex]\((3, 1)\)[/tex]