Simplify.

[tex] \frac{1}{4}\left(1-\frac{2}{3}\right)^2+\frac{1}{3} [/tex]

Enter your answer in the box as a fraction in simplest form.

[tex] \square [/tex]



Answer :

To simplify the expression [tex]\(\frac{1}{4}\left(1-\frac{2}{3}\right)^2+\frac{1}{3}\)[/tex], let's go through it step by step.

1. Calculate the value inside the parentheses:

[tex]\[ 1 - \frac{2}{3} \][/tex]

To subtract these fractions, convert the whole number 1 into a fraction with the same denominator as [tex]\(\frac{2}{3}\)[/tex].

[tex]\[ 1 = \frac{3}{3} \][/tex]

Now, subtract:

[tex]\[ \frac{3}{3} - \frac{2}{3} = \frac{1}{3} \][/tex]

So, the value inside the parentheses is [tex]\(\frac{1}{3}\)[/tex].

2. Square this result:

[tex]\[ \left(\frac{1}{3}\right)^2 = \frac{1}{9} \][/tex]

3. Multiply this squared result by the fraction [tex]\(\frac{1}{4}\)[/tex]:

[tex]\[ \frac{1}{4} \cdot \frac{1}{9} \][/tex]

To multiply two fractions, multiply the numerators together and the denominators together:

[tex]\[ \frac{1 \cdot 1}{4 \cdot 9} = \frac{1}{36} \][/tex]

4. Add the second fraction [tex]\(\frac{1}{3}\)[/tex] to this result:

To add [tex]\(\frac{1}{36}\)[/tex] and [tex]\(\frac{1}{3}\)[/tex], we need a common denominator. The least common multiple of 36 and 3 is 36. Convert [tex]\(\frac{1}{3}\)[/tex] to a fraction with a denominator of 36:

[tex]\[ \frac{1}{3} = \frac{12}{36} \][/tex]

So now, add [tex]\(\frac{1}{36}\)[/tex] and [tex]\(\frac{12}{36}\)[/tex]:

[tex]\[ \frac{1}{36} + \frac{12}{36} = \frac{1 + 12}{36} = \frac{13}{36} \][/tex]

Therefore, the simplified result of the expression [tex]\(\frac{1}{4}\left(1-\frac{2}{3}\right)^2+\frac{1}{3}\)[/tex] is:

[tex]\[ \boxed{\frac{13}{36}} \][/tex]