Let's analyze the given hydrocarbon [tex]$CH_3\left(CH_2\right)_6CH_3$[/tex] and determine its name step-by-step.
1. Identify the structure of the hydrocarbon:
- The given structure consists of a [tex]$CH_3$[/tex] group at the ends, with [tex]$(CH_2)_6$[/tex] in between.
- This means the structure can be written as: [tex]$CH_3 - (CH_2)_6 - CH_3$[/tex].
2. Count the number of carbon atoms:
- There is 1 carbon atom in each of the [tex]$CH_3$[/tex] groups (one at each end).
- There are 6 [tex]$CH_2$[/tex] units, each containing 1 carbon atom.
- Total number of carbon atoms = [tex]$1 + 6 + 1 = 8$[/tex].
3. Determine the prefix:
- Hydrocarbons are named based on the number of carbon atoms they possess.
- The standard prefixes for the number of carbon atoms in hydrocarbons are:
- 1 carbon: Meth-
- 2 carbons: Eth-
- 3 carbons: Prop-
- 4 carbons: But-
- 5 carbons: Pent-
- 6 carbons: Hex-
- 7 carbons: Hept-
- 8 carbons: Oct-
- 10 carbons: Dec-
- For 8 carbon atoms, the prefix is "Oct-".
4. Determine the suffix:
- The given hydrocarbon has only single bonds between the carbon atoms, meaning it is an alkane.
- The suffix for alkanes is "-ane".
5. Name the hydrocarbon:
- Combining the prefix (Oct-) and the suffix (-ane), the name of the hydrocarbon is "Octane".
So, the correct name of the hydrocarbon [tex]$CH_3\left(CH_2\right)_6CH_3$[/tex] is Octane. The answer is:
octane
