Select all of the equations that represent linear relationships.

A. [tex]5 + 2y = 13[/tex]
B. [tex]y = \frac{1}{2} x^2 + 7[/tex]
C. [tex]y - 5 = 2(x - 1)[/tex]
D. [tex]\frac{y}{2} = x + 7[/tex]
E. [tex]x = -4[/tex]



Answer :

Let's analyze each equation to see if it represents a linear relationship.

1. Equation: [tex]\( 5 + 2y = 13 \)[/tex]

To determine if this equation represents a linear relationship, we'll solve for [tex]\( y \)[/tex]:
[tex]\[ 5 + 2y = 13 \][/tex]
Subtract 5 from both sides:
[tex]\[ 2y = 8 \][/tex]
Divide by 2:
[tex]\[ y = 4 \][/tex]
This is a linear equation because it can be written in the form [tex]\( y = mx + b \)[/tex] where [tex]\( m = 0 \)[/tex] and [tex]\( b = 4 \)[/tex]. Therefore, this is a linear equation.

2. Equation: [tex]\( y = \frac{1}{2} x^2 + 7 \)[/tex]

This equation explicitly includes an [tex]\( x^2 \)[/tex] term, which means it is a quadratic equation, not linear. Linear equations can only have variables to the first power. Therefore, this is not a linear equation.

3. Equation: [tex]\( y - 5 = 2(x - 1) \)[/tex]

To determine if this equation represents a linear relationship, we'll rearrange it into the form [tex]\( y = mx + b \)[/tex]:
[tex]\[ y - 5 = 2(x - 1) \][/tex]
Distribute the 2 on the right side:
[tex]\[ y - 5 = 2x - 2 \][/tex]
Add 5 to both sides:
[tex]\[ y = 2x + 3 \][/tex]
This is a linear equation because it can be written in the form [tex]\( y = mx + b \)[/tex] where [tex]\( m = 2 \)[/tex] and [tex]\( b = 3 \)[/tex]. Therefore, this is a linear equation.

4. Equation: [tex]\( \frac{y}{2} = x + 7 \)[/tex]

To determine if this equation represents a linear relationship, we'll solve for [tex]\( y \)[/tex]:
[tex]\[ \frac{y}{2} = x + 7 \][/tex]
Multiply both sides by 2:
[tex]\[ y = 2x + 14 \][/tex]
This is a linear equation because it can be written in the form [tex]\( y = mx + b \)[/tex] where [tex]\( m = 2 \)[/tex] and [tex]\( b = 14 \)[/tex]. Therefore, this is a linear equation.

5. Equation: [tex]\( x = -4 \)[/tex]

This equation represents a vertical line on the coordinate plane, which means that [tex]\( x \)[/tex] remains constant and there is no dependence on [tex]\( y \)[/tex]. Such an equation is still considered linear, though it doesn't fit the [tex]\( y = mx + b \)[/tex] format because it is essentially of the form [tex]\( x = c \)[/tex] where [tex]\( c \)[/tex] represents a constant. Therefore, this is a linear equation.

Based on our analysis:
- Equation [tex]\( 5 + 2y = 13 \)[/tex] is not linear.
- Equation [tex]\( y = \frac{1}{2} x^2 + 7 \)[/tex] is not linear.
- Equation [tex]\( y - 5 = 2(x - 1) \)[/tex] is linear.
- Equation [tex]\( \frac{ y }{2}=x+7 \)[/tex] is linear.
- Equation [tex]\( x = -4 \)[/tex] is linear.

Thus, the equations that represent linear relationships are:
[tex]\[ y - 5 = 2(x - 1) \][/tex]
[tex]\[ \frac{ y }{2}=x+7 \][/tex]
[tex]\[ x=-4 \][/tex]