The graph of the function [tex]$f(x) = (x-3)(x+1)$[/tex] is shown.

Which describes all of the values for which the graph is positive and decreasing?

A. all real values of [tex]$x$[/tex] where [tex][tex]$x \ \textless \ -1$[/tex][/tex]
B. all real values of [tex]$x$[/tex] where [tex]$x \ \textless \ 1$[/tex]
C. all real values of [tex][tex]$x$[/tex][/tex] where [tex]$1 \ \textless \ x \ \textless \ 3$[/tex]
D. all real values of [tex]$x$[/tex] where [tex][tex]$x \ \textgreater \ 3$[/tex][/tex]



Answer :

Let's analyze the function [tex]\( f(x) = (x - 3)(x + 1) \)[/tex].

1. Identify the Roots:
The function touches the x-axis where it equals zero. Solving for [tex]\( f(x) = 0 \)[/tex]:
[tex]\[ (x - 3)(x + 1) = 0 \][/tex]
gives us the roots [tex]\( x = -1 \)[/tex] and [tex]\( x = 3 \)[/tex].

2. Analyze the Parabola:
The function is a quadratic equation and opens upwards because the coefficient of [tex]\( x^2 \)[/tex] in the expanded form (which would be [tex]\( x^2 - 2x - 3 \)[/tex]) is positive.

3. Determine Intervals of Positivity and Negativity:
The intervals change sign at the roots. We analyze the sign of the function in the intervals:
- For [tex]\( x < -1 \)[/tex]: Choose a test point like [tex]\( x = -2 \)[/tex].
[tex]\[ f(-2) = (-2 - 3)(-2 + 1) = (-5)(-1) = 5 \quad \text{(positive)} \][/tex]
- For [tex]\( -1 < x < 3 \)[/tex]: Choose a test point like [tex]\( x = 0 \)[/tex].
[tex]\[ f(0) = (0 - 3)(0 + 1) = (-3)(1) = -3 \quad \text{(negative)} \][/tex]
- For [tex]\( x > 3 \)[/tex]: Choose a test point like [tex]\( x = 4 \)[/tex].
[tex]\[ f(4) = (4 - 3)(4 + 1) = (1)(5) = 5 \quad \text{(positive)} \][/tex]
So the function is positive for [tex]\( x < -1 \)[/tex] and [tex]\( x > 3 \)[/tex], and negative for [tex]\( -1 < x < 3 \)[/tex].

4. Determine Intervals of Decrease:
Finding the vertex of the parabola helps us understand where the function increases or decreases. The vertex lies midway between the roots:
[tex]\[ x = \frac{-1 + 3}{2} = 1 \][/tex]
The function decreases from [tex]\( -\infty \)[/tex] to the vertex at [tex]\( x = 1 \)[/tex] and increases from [tex]\( x = 1 \)[/tex] to [tex]\( + \infty \)[/tex].

5. Intersection of Positivity and Decrease:
The function is positive and decreasing where the intervals of positivity and decrease intersect:
- The function is positive in [tex]\( x < -1 \)[/tex] and [tex]\( x > 3 \)[/tex].
- The function is decreasing in [tex]\( x < 1 \)[/tex].

The intersection of these intervals is [tex]\( x < -1 \)[/tex].

So, the values for which the graph is both positive and decreasing are:
[tex]\[ \boxed{\text{all real values of } x \text{ where } x < -1} \][/tex]