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Eric wants to sell his car that he paid [tex]\$7,000[/tex] for 3 years ago. The car depreciated, or decreased in value, at a constant rate each month over a 3-year period. If [tex]x[/tex] represents the monthly depreciation amount, which expression shows how much Eric can sell his car for today?

A. [tex]7,000 - 3x[/tex]
B. [tex]7,000 + 3x[/tex]
C. [tex]7,000 - 36x[/tex]
D. [tex]7,000 + 36x[/tex]



Answer :

GinnyAnswer
Sure! Let's break this problem down step by step:

1. Understanding the Car's Initial Value: Eric paid \[tex]$7,000 for the car originally. 2. Depreciation Period: The car has been depreciating over a period of 3 years. Since depreciation is happening monthly, we need to convert the years into months. There are 12 months in a year: \[ 3 \text{ years} \times 12 \text{ months/year} = 36 \text{ months} \] 3. Monthly Depreciation Amount: Let \( x \) represent the monthly depreciation amount. 4. Total Depreciation: Over the entire period of 3 years, the total depreciation in the car's value will be: \[ 36 \text{ months} \times x \text{ (monthly depreciation)} = 36x \] 5. Value of the Car Today: To find out how much Eric can sell the car for today, we subtract the total depreciation from the initial value of the car. Initial Value of the car: \$[/tex]7,000

Total Depreciation: [tex]\( 36x \)[/tex]

Thus, the current value of the car (Value Today) is:
[tex]\[ 7000 - 36x \][/tex]

So the expression that shows how much Eric can sell his car for today is:
[tex]\[ \boxed{7000 - 36x} \][/tex]

Therefore, the correct answer is:
[tex]\[ \boxed{c} \][/tex]

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