Which equals the product of [tex]\((t-3)(3x+1)\)[/tex]?

A. [tex]\(2x^2 - 7x + 3\)[/tex]
B. [tex]\(7x^2 + 5k + 3\)[/tex]
C. [tex]\(a - n\)[/tex]
D. [tex]\(6x^2\)[/tex]



Answer :

To find the product of the expression [tex]\((t - 3)(3x + 1)\)[/tex], let's go through the steps of expanding this expression.

Given:
[tex]\[ (t - 3)(3x + 1) \][/tex]

We will use the distributive property to expand this product. The distributive property states that [tex]\(a(b + c) = ab + ac\)[/tex]. Applying this property, we get:

1. Distribute [tex]\(t\)[/tex] to both terms inside the parentheses:
[tex]\[ t \cdot (3x) + t \cdot 1 = 3tx + t \][/tex]

2. Distribute [tex]\(-3\)[/tex] to both terms inside the parentheses:
[tex]\[ -3 \cdot (3x) + (-3) \cdot 1 = -9x - 3 \][/tex]

3. Combine all the distributed parts:
[tex]\[ 3tx + t - 9x - 3 \][/tex]

Therefore, the expanded form of [tex]\((t - 3)(3x + 1)\)[/tex] is:
[tex]\[ 3tx + t - 9x - 3 \][/tex]

So, the product of [tex]\((t - 3)(3x + 1)\)[/tex] is:
[tex]\[ 3tx + t - 9x - 3 \][/tex]