Let's analyze the genetics problem involving two heterozygous rabbits with short fur (Ff). Short fur (F) is dominant over long fur (f).
### Step-by-Step Breakdown:
1. Identify the genotypes:
- Each parent rabbit has the genotype Ff (heterozygous for short fur).
2. Create a Punnett square:
- A Punnett square helps to visualize the combination of alleles from each parent.
```
F f
___________
F | FF | Ff |
___________
f | Ff | ff |
```
3. Determine the possible genotypes of the offspring:
- When we cross Ff (from one parent) with Ff (from the other parent), the possible genotypes for the offspring are:
- FF (short fur)
- Ff (short fur)
- Ff (short fur)
- ff (long fur)
4. Count the genotypes associated with short fur:
- FF: 1 occurrence
- Ff: 2 occurrences
- ff: 1 occurrence
5. Calculate the probability of offspring having short fur:
- There are 4 possible genotypes in total.
- 3 out of these 4 genotypes (FF, Ff, Ff) result in short fur.
- Thus, the probability of having offspring with short fur is 3 out of 4.
### Conclusion:
The chance of two heterozygous short-haired rabbits having offspring with short fur is [tex]\( \frac{3}{4} \)[/tex] or 75%. Therefore, the correct answer is:
○ Three in four
