Point [tex]C[/tex] has the coordinates [tex](-1, 4)[/tex] and point [tex]D[/tex] has the coordinates [tex](2, 0)[/tex].

What is the distance between points [tex]C[/tex] and [tex]D[/tex]?

[tex]
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
[/tex]

[tex]\square[/tex] units



Answer :

To find the distance between two points [tex]\( C \)[/tex] and [tex]\( D \)[/tex] given their coordinates [tex]\( (-1, 4) \)[/tex] and [tex]\( (2, 0) \)[/tex] respectively, we use the distance formula:

[tex]\[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \][/tex]

Here's a step-by-step solution:

1. Identify the coordinates of points [tex]\( C \)[/tex] and [tex]\( D \)[/tex]:
- Point [tex]\( C \)[/tex] has coordinates [tex]\( (x_1, y_1) = (-1, 4) \)[/tex].
- Point [tex]\( D \)[/tex] has coordinates [tex]\( (x_2, y_2) = (2, 0) \)[/tex].

2. Calculate the difference in x-coordinates ([tex]\( \Delta x \)[/tex]):
[tex]\[ \Delta x = x_2 - x_1 = 2 - (-1) = 2 + 1 = 3 \][/tex]

3. Calculate the difference in y-coordinates ([tex]\( \Delta y \)[/tex]):
[tex]\[ \Delta y = y_2 - y_1 = 0 - 4 = -4 \][/tex]

4. Square the differences:
[tex]\[ (\Delta x)^2 = 3^2 = 9 \][/tex]
[tex]\[ (\Delta y)^2 = (-4)^2 = 16 \][/tex]

5. Sum the squares of the differences:
[tex]\[ (\Delta x)^2 + (\Delta y)^2 = 9 + 16 = 25 \][/tex]

6. Calculate the distance by taking the square root of the sum:
[tex]\[ d = \sqrt{25} = 5 \][/tex]

So, the distance between points [tex]\( C \)[/tex] and [tex]\( D \)[/tex] is [tex]\( 5 \)[/tex] units.