The pH can be calculated using the equation [tex]pH = -\log \left( H^{+} \right)[/tex], where [tex]H^{+}[/tex] is the hydronium ion concentration. Find the hydronium ion concentration of a particular vinegar if the pH level is 2.5.

A. [tex]3.162 \times 10^{-3}[/tex]
B. [tex]3.979 \times 10^{-1}[/tex]
C. [tex]3.162 \times 10^{2}[/tex]
D. [tex]9.536 \times 10^{3}[/tex]



Answer :

To find the hydronium ion concentration ([tex]\([H^+]\)[/tex]) of a vinegar solution given its pH level, we can use the relationship between pH and hydronium ion concentration, which is given by the formula:

[tex]\[ pH = -\log [H^+] \][/tex]

In this case, we are given that the pH is 2.5. To find [tex]\([H^+]\)[/tex], we need to rearrange the formula:

[tex]\[ [H^+] = 10^{-\text{pH}} \][/tex]

Substitute the given pH value into the formula:

[tex]\[ [H^+] = 10^{-2.5} \][/tex]

Calculating this, we get:

[tex]\[ [H^+] \approx 0.0031622776601683794 \][/tex]

Which can be written in scientific notation as:

[tex]\[ [H^+] \approx 3.162 \times 10^{-3} \][/tex]

Therefore, the hydronium ion concentration for a vinegar solution with a pH of 2.5 is approximately [tex]\( 3.162 \times 10^{-3} \)[/tex].

Given the choices:
1. [tex]\( 3.162 \times 10^{-3} \)[/tex]
2. [tex]\( 3.979 \times 10^{-1} \)[/tex]
3. [tex]\( 3.162 \times 10^2 \)[/tex]
4. [tex]\( 9.536 \times 10^3 \)[/tex]

The correct answer is:

[tex]\[ 3.162 \times 10^{-3} \][/tex]