Solve the equation.

[tex] |5x + 30| = 15 [/tex]

Enter your answers in the boxes.

[tex] x = \square \text{ or } x = \square [/tex]

Graph the solutions on the number line.

To place an item on the number line, click on the item. Then click the location on the number line where you want to place the item. Drag one side to adjust, if necessary.



Answer :

To solve the equation [tex]\( |5x + 30| = 15 \)[/tex], we need to consider the definition of absolute value. The absolute value of a number is its distance from zero on the number line, regardless of direction. Therefore,

[tex]\[ |5x + 30| = 15 \][/tex]
implies two separate equations:
[tex]\[ 5x + 30 = 15 \][/tex]
and
[tex]\[ 5x + 30 = -15 \][/tex]

Let's solve these equations step by step.

### First Equation: [tex]\( 5x + 30 = 15 \)[/tex]
1. Subtract 30 from both sides:
[tex]\[ 5x + 30 - 30 = 15 - 30 \][/tex]
[tex]\[ 5x = -15 \][/tex]
2. Divide both sides by 5:
[tex]\[ x = \frac{-15}{5} \][/tex]
[tex]\[ x = -3 \][/tex]

### Second Equation: [tex]\( 5x + 30 = -15 \)[/tex]
1. Subtract 30 from both sides:
[tex]\[ 5x + 30 - 30 = -15 - 30 \][/tex]
[tex]\[ 5x = -45 \][/tex]
2. Divide both sides by 5:
[tex]\[ x = \frac{-45}{5} \][/tex]
[tex]\[ x = -9 \][/tex]

So, the solutions to the equation [tex]\( |5x + 30| = 15 \)[/tex] are:
[tex]\[ x = -3 \quad \text{or} \quad x = -9 \][/tex]

### Graph the solutions on the number line
You should place points at [tex]\( x = -3 \)[/tex] and [tex]\( x = -9 \)[/tex] on the number line:

- A point at [tex]\( x = -3 \)[/tex]
- Another point at [tex]\( x = -9 \)[/tex]

The final solutions are:
[tex]\[ x = -3 \quad \text{or} \quad x = -9 \][/tex]