Certainly! Let's tackle both parts of the question step by step.
### A. Convert [tex]\( 25^\circ \text{Celsius} \)[/tex] to [tex]\( \text{Fahrenheit} \)[/tex].
To convert from Celsius to Fahrenheit, we use the following formula:
[tex]\[ F = \left( \frac{9}{5} \times C \right) + 32 \][/tex]
Where [tex]\( C \)[/tex] is the temperature in Celsius and [tex]\( F \)[/tex] is the temperature in Fahrenheit.
For [tex]\( C = 25^\circ \text{C} \)[/tex]:
[tex]\[ F = \left( \frac{9}{5} \times 25 \right) + 32 \][/tex]
[tex]\[ F = \left( 45 \right) + 32 \][/tex]
[tex]\[ F = 77^\circ \text{F} \][/tex]
So, [tex]\( 25^\circ \text{C} \)[/tex] is equal to [tex]\( 77^\circ \text{F} \)[/tex].
### B. Convert 25 degrees Celsius to Kelvin.
To convert from Celsius to Kelvin, we use the following formula:
[tex]\[ K = C + 273.15 \][/tex]
Where [tex]\( C \)[/tex] is the temperature in Celsius and [tex]\( K \)[/tex] is the temperature in Kelvin.
For [tex]\( C = 25^\circ \text{C} \)[/tex]:
[tex]\[ K = 25 + 273.15 \][/tex]
[tex]\[ K = 298.15 \text{K} \][/tex]
So, [tex]\( 25^\circ \text{C} \)[/tex] is equal to [tex]\( 298.15 \text{K} \)[/tex].
### Summary:
A. [tex]\( 25^\circ \text{C} \)[/tex] is converted to [tex]\( 77^\circ \text{F} \)[/tex].
B. [tex]\( 25^\circ \text{C} \)[/tex] is converted to [tex]\( 298.15 \text{K} \)[/tex].
