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For each offspring genotype in the Punnett square you just completed, determine the phenotype. In other words, what is the predicted fur color and eye color of the offspring? Using your Punnett square from the last step, fill in the predicted fraction for each phenotype in the data table below.

\begin{tabular}{|c|c|c|c|c|}
\hline
\multicolumn{1}{|c|}{} & \begin{tabular}{c}
Black Fur and \\
Black Eyes
\end{tabular} & \begin{tabular}{c}
Black Fur and \\
Red Eyes
\end{tabular} & \begin{tabular}{c}
White Fur and \\
Black Eyes
\end{tabular} & \begin{tabular}{c}
White Fur and \\
Red Eyes
\end{tabular} \\
\hline
Predicted Fraction & [tex]$\square / 16$[/tex] & [tex]$\square / 16$[/tex] & [tex]$\square / 16$[/tex] & [tex]$\square / 16$[/tex] \\
\hline
\end{tabular}



Answer :

GinnyAnswer
To determine the phenotype fractions for each genotype combination resulting from a dihybrid cross of BbEe x BbEe, we need to ascertain the predicted fur color and eye color for each possible genotype combination. Below is the step-by-step solution of the predicted fractions for each phenotype:

### Punnett Square Combination:
Parent genotypes: BbEe x BbEe

Possible gametes (combinations of alleles each parent can pass on):
- BE
- Be
- bE
- be

### Phenotype Determination:
- Fur Color: B (dominant) -> Black, b (recessive) -> White
- Eye Color: E (dominant) -> Black, e (recessive) -> Red

### Formation of the Punnett Square:
We form a 4x4 Punnett Square by combining each pair of gametes:

| \\ | BE | Be | bE | be |
|---|----|----|----|----|
| BE | BBEE | BB Ee | Bb EE | Bb Ee |
| Be | BB Ee | BB ee | Bb Ee | Bb ee |
| bE| Bb EE | Bb Ee | bb EE | bb Ee |
| be| Bb Ee | Bb ee | bb Ee | bb ee |

### Genotype to Phenotype Mapping:
- BBEE, BbEE, BB Ee, Bb Ee -> Black Fur and Black Eyes
- BB ee, Bb ee -> Black Fur and Red Eyes
- bb EE, bb Ee -> White Fur and Black Eyes
- bb ee -> White Fur and Red Eyes

### Counting the Phenotype Frequencies:
- Black Fur and Black Eyes:
- BBEE, BbEE, BB Ee, Bb Ee: 9 combinations
- Black Fur and Red Eyes:
- BB ee, Bb ee: 3 combinations
- White Fur and Black Eyes:
- bb EE, bb Ee: 3 combinations
- White Fur and Red Eyes:
- bb ee: 1 combination

### Predicted Phenotype Fractions:
The total number of combinations from the Punnett Square is 16 (4x4).

[tex]\[ \begin{array}{|c|c|c|c|c|} \hline \multicolumn{1}{c|}{} & \begin{tabular}{c} Black Fur and \\ Black Eyes \end{tabular} & \begin{tabular}{c} Black Fur and \\ Red Eyes \end{tabular} & \begin{tabular}{c} White Fur and \\ Black Eyes \end{tabular} & \begin{tabular}{c} White Fur and \\ Red Eyes \end{tabular} \\ \hline Predicted Fraction & \frac{9}{16} & \frac{3}{16} & \frac{3}{16} & \frac{1}{16} \\ \hline \end{array} \][/tex]

Thus, the predicted fractions for each phenotype are:
- Black Fur and Black Eyes: [tex]\(\frac{9}{16}\)[/tex]
- Black Fur and Red Eyes: [tex]\(\frac{3}{16}\)[/tex]
- White Fur and Black Eyes: [tex]\(\frac{3}{16}\)[/tex]
- White Fur and Red Eyes: [tex]\(\frac{1}{16}\)[/tex]

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