Akbar and Birbal start towards each other from their homes, 15 km apart, at 10 a.m. Akbar walks at a constant speed of 4 km/h, while Birbal walks at a constant speed of 6 km/h. When will they meet?



Answer :

Certainly! Let's solve this problem step-by-step:

1. Understanding the Problem:
- The distance between Akbar's and Birbal's homes is 15 kilometers.
- Akbar walks at a constant speed of 4 kilometers per hour.
- Birbal walks at a constant speed of 6 kilometers per hour.
- We need to determine the time at which they will meet.

2. Combined Speed Calculation:
- When two people are walking towards each other, their combined speed is the sum of their individual speeds.
- Therefore, the combined speed of Akbar and Birbal is [tex]\( 4 \text{ kmph} + 6 \text{ kmph} = 10 \text{ kmph} \)[/tex].

3. Time Calculation:
- The formula to calculate the time taken to cover a certain distance is:
[tex]\[ \text{Time} = \frac{\text{Distance}}{\text{Speed}} \][/tex]
- Here, the distance to be covered is 15 kilometers, and the combined speed is 10 kilometers per hour.
- Plugging in the values:
[tex]\[ \text{Time} = \frac{15 \text{ km}}{10 \text{ kmph}} = 1.5 \text{ hours} \][/tex]

4. Converting Time:
- We need to convert 1.5 hours to hours and minutes.
- 1 hour is 60 minutes, so:
[tex]\[ 1.5 \text{ hours} = 1 \text{ hour} + (0.5 \times 60 \text{ minutes}) = 1 \text{ hour} + 30 \text{ minutes} \][/tex]
- Hence, 1.5 hours is equivalent to 1 hour and 30 minutes.

5. Finding the Meeting Time:
- Akbar and Birbal start walking towards each other at 10:00 a.m.
- Adding 1 hour and 30 minutes to their starting time:
[tex]\[ 10:00 \text{ a.m.} + 1 \text{ hour} \, 30 \text{ minutes} = 11:30 \text{ a.m.} \][/tex]

Therefore, Akbar and Birbal will meet at 11:30 a.m.