Algebra

1. Simplify these:
a) [tex]\(\frac{3}{5} x = \frac{2}{3} x\)[/tex]
b) [tex]\(\frac{x^2 - 2x - 48}{x^2 + 4x + 48}\)[/tex]

2. Simplify & expand these:
c) [tex]\(\frac{\log 8}{\log 3^2}\)[/tex]
d) [tex]\(\frac{3 \log 2 + \log 4}{\log 8}\)[/tex]



Answer :

Sure! Let's go through the simplification and expansion step by step.

### (1) Simplify these:

a) [tex]\( \frac{3}{5}x - \frac{2}{3}x \)[/tex]

To simplify this expression, we need to combine the terms by finding a common denominator.

1. Rewrite [tex]\( \frac{3}{5} \)[/tex] and [tex]\( \frac{2}{3} \)[/tex] with a common denominator of 15:
[tex]\[ \frac{3}{5} = \frac{3 \times 3}{5 \times 3} = \frac{9}{15} \][/tex]
[tex]\[ \frac{2}{3} = \frac{2 \times 5}{3 \times 5} = \frac{10}{15} \][/tex]

2. Subtract the fractions:
[tex]\[ \frac{3}{5}x - \frac{2}{3}x = \frac{9}{15}x - \frac{10}{15}x \][/tex]
[tex]\[ = \frac{9x - 10x}{15} \][/tex]
[tex]\[ = \frac{-x}{15} = -\frac{1}{15}x \][/tex]

So, the simplified form is:
[tex]\[ -\frac{1}{15}x \][/tex]

Which simplifies numerically to:
[tex]\[ -0.0666666666666667x \][/tex]

b) [tex]\(\frac{x^2 - 2x - 48}{x^2 + 4x + 48}\)[/tex]

To simplify this rational expression, we look for common factors in the numerator and denominator.

1. Given the numerator:
[tex]\[ x^2 - 2x - 48 \][/tex]

2. Given the denominator:
[tex]\[ x^2 + 4x + 48 \][/tex]

The numerator and the denominator do not have common factors that further simplify in an evident way with basic arithmetic.

Thus, the simplified form remains:
[tex]\[ \frac{x^2 - 2x - 48}{x^2 + 4x + 48} \][/tex]

### (2) Simplify and Expand these:

c) [tex]\(\frac{\log 8}{\log 3^2}\)[/tex]

1. Use the properties of logarithms to simplify:
[tex]\[ \log 3^2 = \log 9 \][/tex]
[tex]\[ \frac{\log 8}{\log 9} \][/tex]

### d) [tex]\(\frac{3 \log 2 + \log 4}{\log 8}\)[/tex]

1. Split and simplify each term using properties of logarithms:
[tex]\[ \log 4 = \log(2^2) = 2 \log 2 \][/tex]

2. Combine the terms in the numerator:
[tex]\[ 3 \log 2 + \log 4 = 3 \log 2 + 2 \log 2 = 5 \log 2 \][/tex]

3. Use properties of logarithms for the denominator:
[tex]\[ \log 8 = \log(2^3) = 3 \log 2 \][/tex]

4. Form the fraction:
[tex]\[ \frac{5 \log 2}{3 \log 2} \][/tex]

5. Since [tex]\(\log 2\)[/tex] is common in both numerator and denominator, they cancel each other out:
[tex]\[ \frac{5 \log 2}{3 \log 2} = \frac{5}{3} \][/tex]

So, the simplified form is:
[tex]\[ \frac{5}{3} \][/tex]