Sure! Here's the step-by-step solution to find the mass of dry solute recovered in the sample:
1. Identify the given data:
- Sample Temperature: 20.5°C
- Boat Mass: 0.720 g
- Boat + Solution Mass: 0.898 g
- Boat + Dry Mass: 0.798 g
2. Understand the question:
We need to find the mass of the dry solute recovered in the sample. The mass of the dry solute can be calculated using the equation:
[tex]\[
\text{Mass of Dry Solute} = (\text{Boat + Dry Mass}) - (\text{Boat Mass})
\][/tex]
3. Perform the calculation:
Plugging in the given values:
[tex]\[
\text{Mass of Dry Solute} = 0.798 \text{ g} - 0.720 \text{ g}
\][/tex]
4. Simplify the expression:
[tex]\[
\text{Mass of Dry Solute} = 0.078 \text{ g}
\][/tex]
So, the mass of dry solute recovered in the sample is [tex]\(0.078 \text{ g}\)[/tex].
For future problems, the equation to find the mass of the dry solute is:
[tex]\[
\text{Mass of Dry Solute} = (\text{Boat + Dry Mass}) - (\text{Boat Mass})
\][/tex]
Here are the given values and intermediate results:
- Boat Mass: [tex]\(0.720 \text{ g}\)[/tex]
- Boat + Dry Mass: [tex]\(0.798 \text{ g}\)[/tex]
- Mass of Dry Solute: [tex]\(0.078 \text{ g}\)[/tex]
- Boat + Solution Mass - Boat + Dry Mass: [tex]\(0.898 \text{ g} - 0.798 \text{ g} = 0.100 \text{ g}\)[/tex]
- Sum of Mass of Dry Solute and Sample Temperature Subtraction: [tex]\(0.078 \text{ g} + 20.5 \text{°C} - 20.5 \text{°C} = 0.078 \text{ g}\)[/tex]
Thus, the mass of the dry solute is [tex]\(0.078 \text{ g}\)[/tex].
