What is the concentration, in grams of solute per mL of solvent, at [tex]20.5^{\circ} C[/tex]?

Mass of solute = 0.078 g

Mass of solvent = 0.100 g

Volume of solvent = 0.100 mL

Remember: [tex]1 \, g \, H_2O = 1 \, mL \, H_2O[/tex]

Be sure to record the equation for future problems.

A. 0.022 g/mL
B. 0.780 g/mL
C. 0.078 g/mL
D. 0.0078 g/mL



Answer :

To determine the concentration of a solute in a solvent, we use the following equation:

[tex]\[ \text{Concentration} = \frac{\text{Mass of solute}}{\text{Volume of solvent}} \][/tex]

Given the problem details:

- Mass of solute, [tex]\(m_{\text{solute}} = 0.078 \, \text{g}\)[/tex]
- Volume of solvent, [tex]\(V_{\text{solvent}} = 0.100 \, \text{mL}\)[/tex] (since [tex]\(1 \, \text{g} \, \text{H}_2\text{O} = 1 \, \text{mL} \, \text{H}_2\text{O}\)[/tex])

Using the equation for concentration:

[tex]\[ \text{Concentration} = \frac{0.078 \, \text{g}}{0.100 \, \text{mL}} \][/tex]

Performing the division gives:

[tex]\[ \text{Concentration} = 0.78 \, \text{g/mL} \][/tex]

So, the concentration of the solute in the solvent at [tex]\(20.5^\circ \text{C}\)[/tex] is:

[tex]\[ \boxed{0.780 \, \text{g/mL}} \][/tex]