Helaine graphed the equation [tex]12x - 4y = 3[/tex]. What was the slope of Helaine's line?

A. [tex]-12[/tex]
B. [tex]-4[/tex]
C. [tex]3[/tex]
D. [tex]12[/tex]



Answer :

To determine the slope of the line represented by the equation [tex]\(12x - 4y = 3\)[/tex], we need to rewrite this equation in the slope-intercept form, which is [tex]\(y = mx + b\)[/tex], where [tex]\(m\)[/tex] represents the slope.

1. Starting with the given equation:
[tex]\[ 12x - 4y = 3 \][/tex]

2. Isolate the term involving [tex]\(y\)[/tex]. To do this, subtract [tex]\(12x\)[/tex] from both sides of the equation:
[tex]\[ -4y = -12x + 3 \][/tex]

3. Next, we need to solve for [tex]\(y\)[/tex]. To do this, divide every term in the equation by [tex]\(-4\)[/tex]:
[tex]\[ y = \frac{-12}{-4}x + \frac{3}{-4} \][/tex]

4. Simplify the fractions:
[tex]\[ y = 3x - \frac{3}{4} \][/tex]

Now the equation is in the slope-intercept form [tex]\(y = mx + b\)[/tex], where the slope [tex]\(m\)[/tex] is the coefficient of [tex]\(x\)[/tex].

Therefore, the slope of Helaine's line is:
[tex]\[ m = 3 \][/tex]

Thus, the correct answer is:
[tex]\[ 3 \][/tex]