A set of solubility data is given below. What is the mass of the dry solute at this temperature?

\begin{tabular}{|c|c|c|c|c|}
\hline
Sample & \begin{tabular}{c}
Temperature \\
[tex]$\left({ }^{\circ} C \right)$[/tex]
\end{tabular} & \begin{tabular}{c}
Boat Mass \\
[tex]$( g )$[/tex]
\end{tabular} & \begin{tabular}{c}
Boat + \\
Solution [tex]$( g )$[/tex]
\end{tabular} & \begin{tabular}{c}
Boat + Dry \\
[tex]$( g )$[/tex]
\end{tabular} \\
\hline
3 & 40.3 & 0.710 & 0.915 & 0.817 \\
\hline
\end{tabular}

A. 0.918 g
B. 0.107 g
C. 0.817 g
D. 0.205 g



Answer :

To determine the mass of the dry solute at the given temperature, we need to follow these steps methodically:

1. Identify the given data:
- Boat Mass: This is the mass of the boat alone, which is [tex]\(0.710 \, g\)[/tex].
- Boat + Solution Mass: This is the combined mass of the boat and the solution, which is [tex]\(0.915 \, g\)[/tex].
- Boat + Dry Mass: This is the combined mass of the boat and the dry solute after the solution has evaporated, which is [tex]\(0.817 \, g\)[/tex].

2. Calculate the mass of the solution:
- To find the mass of the solution, subtract the mass of the boat from the mass of the boat with the solution.
[tex]\[ \text{Mass of Solution} = (\text{Boat + Solution Mass}) - (\text{Boat Mass}) \][/tex]
Substituting the known values:
[tex]\[ \text{Mass of Solution} = 0.915 \, g - 0.710 \, g = 0.205 \, g \][/tex]

3. Calculate the mass of the dry solute:
- To find the mass of the dry solute, subtract the mass of the boat from the mass of the boat with the dry solute.
[tex]\[ \text{Mass of Dry Solute} = (\text{Boat + Dry Mass}) - (\text{Boat Mass}) \][/tex]
Substituting the known values:
[tex]\[ \text{Mass of Dry Solute} = 0.817 \, g - 0.710 \, g = 0.107 \, g \][/tex]

So, based on the calculations:
- The mass of the solution is [tex]\(0.205 \, g\)[/tex].
- The mass of the dry solute is [tex]\(0.107 \, g\)[/tex].

Thus, the mass of the dry solute at the given temperature is [tex]\(0.107 \, g\)[/tex].