Answer :
Certainly! Let's break down each part of the problem.
### First Part:
If a heterozygous male with the genotype Ww is mated with a homozygous recessive female of genotype ww, we can visualize the potential offspring using a Punnett square. The provided Punnett square is as follows:
[tex]\[ \begin{tabular}{|c|c|c|} \hline & W & w \\ \hline w & Ww & ww \\ \hline w & Ww & ww \\ \hline \end{tabular} \][/tex]
This shows the possible genotypes of the offspring:
- Ww (heterozygous)
- ww (homozygous recessive)
The offspring genotypes are: Ww, ww, Ww, and ww.
Among these genotypes, half are heterozygous (Ww) and half are homozygous recessive (ww). Thus, the probability of having heterozygous offspring (Ww) is:
[tex]\[ \frac{\text{Number of Ww genotypes}}{\text{Total genotypes}} = \frac{2}{4} = 0.5 \][/tex]
So, there is a 0.5 (or 50%) chance of the offspring being heterozygous.
### Second Part:
If the heterozygous, Ww, is crossed with a homozygous dominant, WW, we analyze the offspring with another Punnett square. The provided Punnett square is:
[tex]\[ \begin{tabular}{|c|c|c|} \hline & W & w \\ \hline W & WW & WW \\ \hline W & WW & WW \\ \hline \end{tabular} \][/tex]
This shows the possible genotypes of the offspring:
- WW (homozygous dominant)
The offspring genotypes are: WW, WW, WW, and WW.
Among these genotypes, none are homozygous recessive (ww). Thus, the probability of having a homozygous recessive offspring (ww) is:
[tex]\[ \frac{\text{Number of ww genotypes}}{\text{Total genotypes}} = \frac{0}{4} = 0.0 \][/tex]
So, the probability of having a homozygous recessive offspring is 0.0 (or 0%).
### Conclusion:
From the drop-down menu, you should select:
1. "0.5" (for the probability of heterozygous offspring from the first cross)
2. "0.0" (for the probability of homozygous recessive offspring from the second cross)
Thus, the answers are:
- If a heterozygous male with the genotype Ww is mated with a homozygous recessive female of genotype ww, there is a 0.5 chance that of the offspring will be heterozygous.
- If the heterozygous, Ww, is crossed with a homozygous dominant, WW, then the probability of having a homozygous recessive offspring is 0.0.
### First Part:
If a heterozygous male with the genotype Ww is mated with a homozygous recessive female of genotype ww, we can visualize the potential offspring using a Punnett square. The provided Punnett square is as follows:
[tex]\[ \begin{tabular}{|c|c|c|} \hline & W & w \\ \hline w & Ww & ww \\ \hline w & Ww & ww \\ \hline \end{tabular} \][/tex]
This shows the possible genotypes of the offspring:
- Ww (heterozygous)
- ww (homozygous recessive)
The offspring genotypes are: Ww, ww, Ww, and ww.
Among these genotypes, half are heterozygous (Ww) and half are homozygous recessive (ww). Thus, the probability of having heterozygous offspring (Ww) is:
[tex]\[ \frac{\text{Number of Ww genotypes}}{\text{Total genotypes}} = \frac{2}{4} = 0.5 \][/tex]
So, there is a 0.5 (or 50%) chance of the offspring being heterozygous.
### Second Part:
If the heterozygous, Ww, is crossed with a homozygous dominant, WW, we analyze the offspring with another Punnett square. The provided Punnett square is:
[tex]\[ \begin{tabular}{|c|c|c|} \hline & W & w \\ \hline W & WW & WW \\ \hline W & WW & WW \\ \hline \end{tabular} \][/tex]
This shows the possible genotypes of the offspring:
- WW (homozygous dominant)
The offspring genotypes are: WW, WW, WW, and WW.
Among these genotypes, none are homozygous recessive (ww). Thus, the probability of having a homozygous recessive offspring (ww) is:
[tex]\[ \frac{\text{Number of ww genotypes}}{\text{Total genotypes}} = \frac{0}{4} = 0.0 \][/tex]
So, the probability of having a homozygous recessive offspring is 0.0 (or 0%).
### Conclusion:
From the drop-down menu, you should select:
1. "0.5" (for the probability of heterozygous offspring from the first cross)
2. "0.0" (for the probability of homozygous recessive offspring from the second cross)
Thus, the answers are:
- If a heterozygous male with the genotype Ww is mated with a homozygous recessive female of genotype ww, there is a 0.5 chance that of the offspring will be heterozygous.
- If the heterozygous, Ww, is crossed with a homozygous dominant, WW, then the probability of having a homozygous recessive offspring is 0.0.