Answered

Select the correct answer from each drop-down menu.

If a heterozygous male with the genotype [tex]Ww[/tex] is mated with a homozygous recessive female of genotype [tex]ww[/tex], there is a chance that [tex]\square[/tex] of the offspring will be heterozygous.

\begin{tabular}{|c|c|c|}
\hline & W & w \\
\hline w & Ww & ww \\
\hline w & Ww & ww \\
\hline
\end{tabular}

If the heterozygous, [tex]Ww[/tex], is crossed with a homozygous dominant, [tex]WW[/tex], then the probability of having a homozygous recessive offspring is [tex]\square[/tex].

\begin{tabular}{|c|c|c|}
\hline & W & w \\
\hline W & WW & WW \\
\hline W & WW & WW \\
\hline
\end{tabular}



Answer :

Certainly! Let's break down each part of the problem.

### First Part:
If a heterozygous male with the genotype Ww is mated with a homozygous recessive female of genotype ww, we can visualize the potential offspring using a Punnett square. The provided Punnett square is as follows:

[tex]\[ \begin{tabular}{|c|c|c|} \hline & W & w \\ \hline w & Ww & ww \\ \hline w & Ww & ww \\ \hline \end{tabular} \][/tex]

This shows the possible genotypes of the offspring:
- Ww (heterozygous)
- ww (homozygous recessive)

The offspring genotypes are: Ww, ww, Ww, and ww.

Among these genotypes, half are heterozygous (Ww) and half are homozygous recessive (ww). Thus, the probability of having heterozygous offspring (Ww) is:

[tex]\[ \frac{\text{Number of Ww genotypes}}{\text{Total genotypes}} = \frac{2}{4} = 0.5 \][/tex]

So, there is a 0.5 (or 50%) chance of the offspring being heterozygous.

### Second Part:
If the heterozygous, Ww, is crossed with a homozygous dominant, WW, we analyze the offspring with another Punnett square. The provided Punnett square is:

[tex]\[ \begin{tabular}{|c|c|c|} \hline & W & w \\ \hline W & WW & WW \\ \hline W & WW & WW \\ \hline \end{tabular} \][/tex]

This shows the possible genotypes of the offspring:
- WW (homozygous dominant)

The offspring genotypes are: WW, WW, WW, and WW.

Among these genotypes, none are homozygous recessive (ww). Thus, the probability of having a homozygous recessive offspring (ww) is:

[tex]\[ \frac{\text{Number of ww genotypes}}{\text{Total genotypes}} = \frac{0}{4} = 0.0 \][/tex]

So, the probability of having a homozygous recessive offspring is 0.0 (or 0%).

### Conclusion:
From the drop-down menu, you should select:
1. "0.5" (for the probability of heterozygous offspring from the first cross)
2. "0.0" (for the probability of homozygous recessive offspring from the second cross)

Thus, the answers are:
- If a heterozygous male with the genotype Ww is mated with a homozygous recessive female of genotype ww, there is a 0.5 chance that of the offspring will be heterozygous.
- If the heterozygous, Ww, is crossed with a homozygous dominant, WW, then the probability of having a homozygous recessive offspring is 0.0.