To determine which of the given numbers (0, 1, 3) can replace the box in the inequality [tex]\(\square > 0\)[/tex] to make it a true statement, we need to evaluate the inequality for each number:
1. Check if 0 can replace the box:
[tex]\[
0 > 0
\][/tex]
- Evaluating this, we see that [tex]\(0\)[/tex] is not greater than [tex]\(0\)[/tex]; therefore, this statement is false.
2. Check if 1 can replace the box:
[tex]\[
1 > 0
\][/tex]
- Evaluating this, we see that [tex]\(1\)[/tex] is greater than [tex]\(0\)[/tex]; therefore, this statement is true.
3. Check if 3 can replace the box:
[tex]\[
3 > 0
\][/tex]
- Evaluating this, we see that [tex]\(3\)[/tex] is greater than [tex]\(0\)[/tex]; therefore, this statement is true.
From these evaluations, we can conclude that the numbers 1 and 3 can replace the box to make the inequality [tex]\(\square > 0\)[/tex] true. Hence:
- For the number 0, the statement is false.
- For the number 1, the statement is true.
- For the number 3, the statement is true.
So, the numbers 1 and 3 are the correct choices that make the inequality true.
