Which ordered pair is a solution to the following system of inequalities?

[tex]\[
\begin{array}{l}
y \leq -x^2 + 8x \\
y \ \textgreater \ x^2 - 3
\end{array}
\][/tex]

A. [tex]\((-1, 4)\)[/tex]
B. [tex]\((0, 9)\)[/tex]
C. [tex]\((2, 7)\)[/tex]
D. [tex]\((4, 3)\)[/tex]



Answer :

To determine which ordered pair is a solution to the system of inequalities:
[tex]\[ \begin{array}{l} y \leq -x^2 + 8x \\ y > x^2 - 3 \end{array} \][/tex]

we need to check each given ordered pair against both inequalities.

Step-by-Step Checking:

1. Ordered Pair [tex]\((-1, 4)\)[/tex]:

- Check [tex]\( y \leq -x^2 + 8x \)[/tex]:
[tex]\[ 4 \leq -(-1)^2 + 8(-1) \implies 4 \leq -1 - 8 \implies 4 \leq -9 \][/tex]
This is false.

- Since it does not satisfy the first inequality, we don't need to check the second inequality for this pair.

2. Ordered Pair [tex]\((0, 9)\)[/tex]:

- Check [tex]\( y \leq -x^2 + 8x \)[/tex]:
[tex]\[ 9 \leq -(0)^2 + 8(0) \implies 9 \leq 0 \][/tex]
This is false.

- Since it does not satisfy the first inequality, we don't need to check the second inequality for this pair.

3. Ordered Pair [tex]\((2, 7)\)[/tex]:

- Check [tex]\( y \leq -x^2 + 8x \)[/tex]:
[tex]\[ 7 \leq -(2)^2 + 8(2) \implies 7 \leq -4 + 16 \implies 7 \leq 12 \][/tex]
This is true.

- Check [tex]\( y > x^2 - 3 \)[/tex]:
[tex]\[ 7 > (2)^2 - 3 \implies 7 > 4 - 3 \implies 7 > 1 \][/tex]
This is also true.

Since both inequalities are satisfied, [tex]\((2, 7)\)[/tex] is a solution to the system.

4. Ordered Pair [tex]\((4, 3)\)[/tex]:

- Check [tex]\( y \leq -x^2 + 8x \)[/tex]:
[tex]\[ 3 \leq -(4)^2 + 8(4) \implies 3 \leq -16 + 32 \implies 3 \leq 16 \][/tex]
This is true.

- Check [tex]\( y > x^2 - 3 \)[/tex]:
[tex]\[ 3 > (4)^2 - 3 \implies 3 > 16 - 3 \implies 3 > 13 \][/tex]
This is false.

- Since it does not satisfy the second inequality, [tex]\((4, 3)\)[/tex] is not a solution.

Based on the evaluations, the ordered pair [tex]\((2, 7)\)[/tex] satisfies both inequalities. Thus, the ordered pair that is a solution to the given system of inequalities is:

[tex]\(\boxed{(2, 7)}\)[/tex]