Last week, Lindsay earned [tex]\$10[/tex] per hour plus a [tex]\$60[/tex] bonus for good job performance. She spends [tex]\frac{1}{15}[/tex] of her paycheck on dinner with friends. If she had not earned the bonus, the amount she spent on dinner would have been [tex]\frac{1}{10}[/tex] of her paycheck.

Which equation can be used to find [tex]h[/tex], the number of hours Lindsay worked last week?

A. [tex]\frac{1}{15}(10h + 60) = \frac{1}{10}(10h)[/tex]
B. [tex]\frac{1}{15}(10h + 60h) = \frac{1}{10}(10h)[/tex]
C. [tex]\frac{1}{15}h(10 + 60) = \frac{1}{10}h(10)[/tex]
D. [tex]\frac{1}{15}(10 + 80h) = \frac{1}{10}(10h)[/tex]



Answer :

Let's denote the number of hours Lindsay worked last week as [tex]\( h \)[/tex].

Step-by-step solution:

1. Calculate Lindsay's Total Earnings:
- Lindsay earns [tex]$10 per hour and worked for \( h \) hours - Therefore, her earnings from working \( h \) hours is \( 10h \) dollars. - She also receives a $[/tex]60 bonus for her good job performance.
- Thus, her total earnings are:
[tex]\[ 10h + 60 \][/tex]

2. Calculate the Amount Spent on Dinner with Bonus:
- She spends [tex]\(\frac{1}{15}\)[/tex] of her paycheck on dinner.
- Her paycheck with the bonus is [tex]\( 10h + 60 \)[/tex] dollars.
- Hence, the amount she spends on dinner is:
[tex]\[ \frac{1}{15}(10h + 60) \][/tex]

3. Calculate the Amount Spent on Dinner without Bonus:
- Without the $60 bonus, her earnings would just be [tex]\( 10h \)[/tex] dollars.
- She would spend [tex]\(\frac{1}{10}\)[/tex] of this amount on dinner.
- Hence, the amount she spends on dinner without the bonus is:
[tex]\[ \frac{1}{10}(10h) \][/tex]

4. Set Up the Equation:
- According to the problem, we know these two amounts should be equal for the chosen number of hours [tex]\( h \)[/tex]:
[tex]\[ \frac{1}{15}(10h + 60) = \frac{1}{10}(10h) \][/tex]

Therefore, the correct equation to find [tex]\( h \)[/tex] is:
[tex]\[ \frac{1}{15}(10 h + 60) = \frac{1}{10}(10 h) \][/tex]

This matches the first option provided in the multiple-choice answers.

So, the correct equation is:
[tex]\[ \frac{1}{15}(10 h + 60) = \frac{1}{10}(10 h). \][/tex]