Solve [tex]$3kx + 24 = 9kx$[/tex] for [tex]$x$[/tex].

A. [tex]$x = \frac{2}{k}$[/tex]
B. [tex][tex]$x = \frac{4}{k}$[/tex][/tex]
C. [tex]$x = -\frac{2}{k}$[/tex]
D. [tex]$x = -\frac{4}{k}$[/tex]



Answer :

To solve the equation [tex]\(3kx + 24 = 9kx\)[/tex] for [tex]\(x\)[/tex], follow these steps:

1. Start with the given equation:
[tex]\[ 3kx + 24 = 9kx \][/tex]

2. Subtract [tex]\(3kx\)[/tex] from both sides of the equation to isolate the terms involving [tex]\(x\)[/tex]:
[tex]\[ 3kx + 24 - 3kx = 9kx - 3kx \][/tex]
Simplifying the left and right sides, we get:
[tex]\[ 24 = 6kx \][/tex]

3. Solve for [tex]\(x\)[/tex] by isolating [tex]\(x\)[/tex]. To do this, divide both sides of the equation by [tex]\(6k\)[/tex]:
[tex]\[ x = \frac{24}{6k} \][/tex]

4. Simplify the fraction on the right side:
[tex]\[ x = \frac{24}{6k} = \frac{24 \div 6}{k \div 6} = \frac{4}{k} \][/tex]

Therefore, the solution to the equation [tex]\(3kx + 24 = 9kx\)[/tex] is:

[tex]\( \boxed{x = \frac{4}{k}} \)[/tex]

So the correct answer is:
B. [tex]\( x = \frac{4}{k} \)[/tex]