10. A sports store buys a shipment of catcher's mitts at the beginning of the year. By year's end, the store has sold 100 mitts and has 150 left. How many mitts did the store have at the beginning of the year?

Let [tex]$x$[/tex] stand for the number of catcher's mitts the store had at the beginning of the year:

[tex]\[ x - 100 = 150 \][/tex]

How would you solve this equation? Circle the answer.

A. Subtract 100 from both sides.
B. Add 100 to both sides.
C. Subtract 150 from both sides.



Answer :

To solve the equation [tex]\( x - 100 = 150 \)[/tex] for [tex]\( x \)[/tex], we need to isolate [tex]\( x \)[/tex] on one side of the equation. Here’s how you can do it step-by-step:

1. Begin with the given equation:
[tex]\[ x - 100 = 150 \][/tex]

2. To isolate [tex]\( x \)[/tex], you need to eliminate the [tex]\( -100 \)[/tex] from the left side. To do this, add 100 to both sides of the equation:
[tex]\[ x - 100 + 100 = 150 + 100 \][/tex]

3. Simplify both sides:
[tex]\[ x = 250 \][/tex]

So, the store had 250 catcher's mitts at the beginning of the year.

The correct step to solve the equation is to add 100 to both sides. Hence, the answer is:

b. Add 100 to both sides.