Write the equation of the line that passes through [tex]\((7, 6)\)[/tex] and [tex]\((-1, 2)\)[/tex] in slope-intercept form.

A. [tex]\(y = \frac{1}{2}x + \frac{19}{2}\)[/tex]

B. [tex]\(y = 2x + 4\)[/tex]

C. [tex]\(y = \frac{1}{2}x + \frac{5}{2}\)[/tex]

D. [tex]\(y = -\frac{1}{2}x + \frac{3}{2}\)[/tex]



Answer :

Alright, let's write the equation of the line that passes through the points [tex]\((7, 6)\)[/tex] and [tex]\((-1, 2)\)[/tex]. To do this, we will follow these steps:

1. Determine the slope [tex]\(m\)[/tex] of the line:
The formula for the slope [tex]\(m\)[/tex] between two points [tex]\((x_1, y_1)\)[/tex] and [tex]\((x_2, y_2)\)[/tex] is:
[tex]\[ m = \frac{y_2 - y_1}{x_2 - x_1} \][/tex]
Plugging in the points [tex]\((7, 6)\)[/tex] and [tex]\((-1, 2)\)[/tex]:
[tex]\[ m = \frac{2 - 6}{-1 - 7} = \frac{-4}{-8} = \frac{1}{2} \][/tex]

2. Identify the y-intercept [tex]\(b\)[/tex] of the line:
The slope-intercept form of a line is given by [tex]\(y = mx + b\)[/tex], where [tex]\(m\)[/tex] is the slope and [tex]\(b\)[/tex] is the y-intercept. We can use one of the points and the slope to solve for [tex]\(b\)[/tex]. Let's use the point [tex]\((7, 6)\)[/tex]. Substitute [tex]\(m = \frac{1}{2}\)[/tex], [tex]\(x = 7\)[/tex] and [tex]\(y = 6\)[/tex] into the equation:
[tex]\[ 6 = \frac{1}{2}(7) + b \][/tex]
Solving for [tex]\(b\)[/tex]:
[tex]\[ 6 = \frac{7}{2} + b \][/tex]
[tex]\[ 6 - \frac{7}{2} = b \][/tex]
[tex]\[ \frac{12}{2} - \frac{7}{2} = b \][/tex]
[tex]\[ \frac{5}{2} = b \][/tex]

3. Write the equation in slope-intercept form:
Now that we have the slope [tex]\(m\)[/tex] and the y-intercept [tex]\(b\)[/tex], we can write the equation of the line:
[tex]\[ y = \frac{1}{2}x + \frac{5}{2} \][/tex]

So, the equation of the line that passes through [tex]\((7, 6)\)[/tex] and [tex]\((-1, 2)\)[/tex] in slope-intercept form is:
[tex]\[ \boxed{y = \frac{1}{2} x + \frac{5}{2}} \][/tex]

Among the given options, the correct one is:
[tex]\[ y = \frac{1}{2} x + \frac{5}{2} \][/tex]